A nucleus represented by the symbol has:
1. | Z protons and A –Z neutrons |
2. | Z protons and A neutrons |
3. | A protons and Z –A neutrons |
4. | Z neutrons and A –Z protons |
As compared to 12C atom, 14C atom has:
1. | two extra protons and two extra electrons |
2. | two extra protons but no extra electron |
3. | two extra neutrons and no extra electron |
4. | two extra neutrons and two extra electrons |
The volume occupied by an atom is greater than the volume of the nucleus by a factor of about:
1. \(10\)
2. \(10^5\)
3. \(10^{10}\)
4. \(10^{15}\)
Two nuclei have their mass numbers in the ratio of \(1:3.\) The ratio of their nuclear densities would be:
1. \(1:3\)
2. \(3:1\)
3. \((3)^{1/3}:1\)
4. \(1:1\)
1. | \(25:16\) | 2. | \(1:1\) |
3. | \(4:5\) | 4. | \(5:4\) |
Assertion (A): | The density of nucleus is much higher than that of ordinary matter. |
Reason (R): | \(10^5\) times smaller. | Most of the mass of the atom is concentrated in the nucleus while the size of this nucleus is almost
1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
3. | (A) is True but (R) is False. |
4. | Both (A) and (R) are False. |
If \(M(A,~Z)\), \(M_p\), and \(M_n\) denote the masses of the nucleus \(^{A}_{Z}X,\) proton, and neutron respectively in units of \(u\) (\(1~u=931.5~\text{MeV/c}^2\)) and represent its binding energy \((BE)\) in \(\text{MeV}\). Then:
1. | \(M(A, Z) = ZM_p + (A-Z)M_n- \frac{BE}{c^2}\) |
2. | \(M(A, Z) = ZM_p + (A-Z)M_n+ BE\) |
3. | \(M(A, Z) = ZM_p + (A-Z)M_n- BE\) |
4. | \(M(A, Z) = ZM_p + (A-Z)M_n+ \frac{BE}{c^2}\) |