If the density of gold nucleus is X, then the density of silver nucleus will be:

1.  2X

2. $\frac{X}{3}$

3.  4X

4.  X 

The volume (V) of a nucleus is related to its mass (M) as:

1.  $V$ $\propto$ $M$

2.  $V$ $\propto$ $\frac{1}{M}$

3.  $V$ $\propto$ $M^3$

4.  $V$ $\propto$ $\frac{1}{M^3}$

Two nuclei have their mass numbers in the ratio of \(1:3.\) The ratio of their nuclear densities would be:
1. \(1:3\)
2. \(3:1\)
3. \((3)^{1/3}:1\)
4. \(1:1\)

The stable nucleus that has a radius half of the radius of $F{e}^{56}$ is:

1. $L{i}^7$ 

2. $N{a}^{21}$

3. $S^{16}$

4. $C{a}^{40}$

If the nuclear density of the material of atomic mass 27 is \(3\rho _{0},\)$t$hen the nuclear density of the material of atomic mass 125 is:

1.  5${\rho }_0$

2.  3${\rho }_0$

3.  $\frac{5}{3}$${\rho }_0$

4.  ${\rho }_0$

The energy equivalent of one atomic mass unit is:

1. $1.6\times {10}^{-19}$ $J$ 

2. $6.02\times {10}^{23}$ $J$

3. 931 MeV 

4. 9.31 MeV

A nuclear reaction along with the masses of the particle taking part in it is as follows;

$A + B \to C + D + Q MeV$
$1.002 1.004 1.001 1.003$
$amu amu amu amu$

The energy Q liberated in the reaction is:

1. 1.234 MeV

2. 0.931 MeV

3. 0.465 MeV

4. 1.862 MeV

Determine the energy released in the process:

${}_{1}H_2+{}_{1}H_2\to {}_{2}H{e}^4+Q$

Given: M $\left({}_{1}H_2\right)$= 2.01471 amu

            M$\left({}_{2}H{e}^4\right)$= 4.00388 amu

1. 3.79 MeV
2.13.79 MeV
3. 0.79 MeV 
4. 23.79 MeV

If an electron and a positron annihilate, then the energy released is:

1. $3.2\times {10}^{-13}$ $\mathrm{J}$       

2. $1.6\times {10}^{-13}$ $\mathrm{J}$

3. $4.8\times {10}^{-13}$ $\mathrm{J}$           

4. $6.4\times {10}^{-13}$ $\mathrm{J}$

The energy required in \(\mathrm{MeV} / \mathrm{c}^2\) to separate \({ }_8^{16} \mathrm{O}\) into its constituents is:
(Given mass defect for \({ }_8^{16} \mathrm{O}=0.13691 \mathrm{u}\))
1. \(127.5\)
2. \(120.0\)
3. \(222.0\)
4. \(119.0\)