Q. No.For the reaction:
H2S (g) + Cl2 (g) → 2 HCl (g) + S (s)
The correct statement(s) in the balanced equation is(are):
a. H2S is oxidised
b. Cl2 is reduced
c. H2S is reduced
d. Cl2 is oxidised
1. a, b
2. b, c
3. c, d
4. a, d
2 Na(s) + H2(g) → 2 NaH (s)
The incorrect statement among the following regarding above mentioned reaction is-
1. Na gets oxidised
2. It is a redox reaction
3. NaH is an ionic hydride
4. None of the above
Match the items in column I with column II.
(O.S = oxidation state)
| Column I | Column II |
| a. Au O.S in HAuCl4 | i. +2 |
| b. Tl O.S in Tl2O | ii. +1 |
| c. Fe O.S in FeO | iii. +3 |
| d. Cu O.S in CuI |
1. a=i; b=ii; c=iii; d=ii
2. a=iii; b=i; c=ii; d=ii
3. a=iii; b=ii; c=i; d=ii
4. a=ii; b=i; c=iii; d=ii
2Cu2O(s) + Cu2S(s) → 6Cu(s) + SO2(g)
The correct statement among the following regarding above mentioned reaction is-
1. Cu is reduced and Cu(I) is an reductant
2. Sulphur is reduced and S in Cu2S acts as oxidant
3. Cu(I) is an oxidant and Cu(I) is reduced.
4. Sulphur is reduced and Cu is oxidised
The species among the following that does not show a disproportionation reaction is-
ClO–, ClO2–, \(ClO_{3}^{-}\) and ClO4–
1. ClO–
2. ClO2–
3. ClO4–
4. \(ClO_{3}^{-}\)
Match the items in column I with the items in column II.
| Column I | Column II |
| a. N2 (g) + O2 (g) → 2 NO (g) | i. Disproportionation redox reaction |
| b. 2Pb(NO3)2(s) → 2PbO(s) + 4 NO2 (g) + O2 (g) | ii. Decomposition redox reaction |
| c. NaH(s) + H2O(l) → NaOH(aq) + H2 (g) | iii. Combination redox reactions |
| d. 2NO2(g) + 2OH–(aq) → NO2–(aq) + NO3– (aq) + H2O(l) | iv. Displacement redox reaction |
1. a=iii; b=ii; c=iv; d=i
2. a=iii; b=iv; c=i; d=ii
3. a=ii; b=iii; c=iv; d=i
4. a=iv; b=i; c=iii; d=ii
Consider the following reaction:
Pb3O4 + 8HCl → A + B + 4H2O
A and B are respectively-
1. A= PbCl4; B= PbCl2
2. A= PbCl2; B= Cl2
3. A= PbCl4; B=Cl2
4. A = PbCl2; B = O2
Consider the following equation:
Cr2O72–(aq) + 3SO32– (aq)+ 8H+(aq) → A + B +4H2O(l)
The product A and B are respectively-
1. 2Cr2+; 3SO2
2. 2Cr+; S2O7 2-
3. 2Cr3+; 3SO4 2-
4. 2Cr3+; 3HSO42-
aMnO4–(aq) + bBr–(aq) + cH2O(l) → dMnO2(s) + eBrO3– (aq) + fOH–(aq)
The value of c, d and f in the above mentioned reaction are respectively-
1. c=1; d=2; f=2
2. c=2; d=1; f=2
3. c=2; d=2; f=1
d. c=1; d=1; f=1
Permanganate(VII) ion, MnO4– in basic solution oxidizes iodide ion, I– to produce molecular iodine (I2) and manganese (IV) oxide (MnO2). The reaction is as follows:
aI–(aq) + bMnO4–(aq) + cH2O(l) → dI2(s) + eMnO2(s) + fOH–(aq)
The value of b, d and f are-
1. b=2; d=3; f=8
2. b=1; d=3; f=8
3. b=3; d=8; f=2
4. b=8; d=3; f=2
© 2024 GoodEd Technologies Pvt. Ltd.