The correct order of N-compounds in its decreasing order of oxidation states is -

1. ${\mathrm{HNO}}_3,$ $\mathrm{NO},$ ${\mathrm{N}}_2,$ ${\mathrm{NH}}_4\mathrm{Cl}$

2. ${\mathrm{HNO}}_3, \mathrm{NO}, {\mathrm{NH}}_4\mathrm{Cl}, {\mathrm{N}}_2$

3. ${\mathrm{HNO}}_3, {\mathrm{NH}}_4\mathrm{Cl}, \mathrm{NO}, {\mathrm{N}}_2$

4. ${\mathrm{NH}}_4\mathrm{Cl}, {\mathrm{N}}_2, \mathrm{NO}, {\mathrm{HNO}}_3$

For the redox reaction,
 a${\mathrm{MnO}}_4^{-}+{\mathrm{bC}}_2{\mathrm{O}}_4^{2-}+{\mathrm{cH}}^{+}\to {\mathrm{dMn}}^{2+}+{\mathrm{eCO}}_2+{\mathrm{fH}}_2\mathrm{O}$
the correct stoichiometric coefficients of the reactants a, b, and c respectively for the balanced equation are: 

1. 16, 5, 2
2. 2, 5, 16
3. 2, 16, 5
4. 5, 16, 2

Among the following the correct order of acidity is-

1. HClO < HClO₂< HClO₃< HClO₄
2. HClO₂< HClO < HClO₃< HClO₄
3. HClO₄< HClO₂< HClO < HClO₃
4. HClO₃< HClO₄< HClO₂< HClO