Column I	Column II
a.	i. Primary amine
b.	ii. Secondary amine
c.	iii. Tertiary amine
d.

1. a-iii; b-iii; c-i; d-ii
2. a-ii; b-iii c-i; d-ii
3. a-i; b-iii c-i; d-ii
4. a-ii; b-i c-i; d-ii

1. 7
2. 6
3. 8
4. 9

Benzene  \(\xrightarrow[conc. HNO_{3}]{conc. H_{2}SO_{4}}\) A \(\xrightarrow[ethanol]{H_{2}, Pd}\) B

B is-

1. Aniline
2. Benzene
3. Cyclohexylamine
4. 1-Nitrocyclohexane
 

Consider the reactions,

(i) CH₃CH₂CH₂NH₂+HCl→ A

(ii) (C₂H₅)₃N+HCl→ B

Products A and B are respectively-

1. CH₃CH₂CH₂NHCl ; (C₂H₅)₃NCl
2. CH₃CH₂CH₂Cl  ; (C₂H₅)₃NCl
3. CH₃CH₂CH₂NH₃⁺ ; (C₂H₅)₃NH⁺ 
4. None of the above

Aniline with excess of methyl iodide in the presence of sodium carbonate solution gives: 

1. N, N, N−trimethylanilinium carbonate.
2. N, N-dimethylaniline.
3. N, N-diethylaniline.
4.  N, N, N−triethylanilinium carbonate.

Aniline + benzoyl chloride  \(\xrightarrow[]{Base}\) Product

The product produced in the above-mentioned reaction is:

1. N-phenylbenzamide
2. Chlorobenzene
3. N-chlorobenzamide
4. None of the above
 

1. a. Br₂/H₂O; b- NaNO₂/HCl; c- H₃PO₂ /H₂O

2. a-NaNO₂/HCl; b- H₃PO₂ /H₂O; c-Br₂/H₂O

3. a-NaNO₂/HCl; b-H₂O; c-Br₂/H₂O

4. None of the above