Assertion (A): | A reaction can have zero activation energy. |
Reason (R): | The minimum extra amount of energy absorbed by reactant molecules so that their energy becomes equal to threshold value, is called activation energy. |
1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
3. | (A) is true but (R) is false. |
4. | (A) is false but (R) is true. |
1. | \( Rate =k[A]^0[B]^2 \) | 2. | \( Rate =k[A][B] \) |
3. | \(Rate=k[A]^{1 / 2}[B]^2 \) | 4. | \(Rate =k[A]^{-1 / 2}[B]^{3 / 2}\) |
1. | \(-\Delta [A] \over \Delta t\) | 2. | \(-3\Delta [A] \over 2\Delta t\) |
3. | \(-2\Delta [A] \over 3\Delta t\) | 4. | \(\Delta [A] \over \Delta t\) |
1. | zero order (y=rate and x=concentration), first order (y=rate and x=t1/2) |
2. | zero order (y=concentration and x=time), first order (y=t1/2 and x = concentration) |
3. | zero order (y=concentration and x= time), first order (y=rate constant and x= concentration) |
4. | zero order (y=rate and x=concentration), first order (y=t1/2 and x = concentration) |
For a first-order reaction A \(\rightarrow\) Products, initial concentration of A is 0.1 M, which becomes 0.001 M after 5 minutes. Rate constant for the reaction in min-1 is
1. | 0.2303 | 2. | 1.3818 |
3. | 0.9212 | 4. | 0.4606 |
For the reaction, 2A → B, rates= k[A]2. If the concentration of reactant is doubled, then the:
(a) | rate of reaction will be doubled. |
(b) | rate constant will remain unchanged, however rate of reaction is directly proportional to the rate constant. |
(c) | rate constant will change since the rate of reaction and rate constant are directly proportional to each other. |
(d) | rate of reaction will increase by four times. |
Identify the set of correct statements & choose the correct answer from the options given below:
1. | (a) and (c) only | 2. | (a) and (b) only |
3. | (b) and (d) only | 4. | (c) and (d) only |
The plot of ln k vs \({1 \over T}\) for the following reaction
\(2N_2O_5(g) \rightarrow 4NO_2 (g) + O_2(g) \) gives a straight line with the slope of the line equal to \(-1.0 \times 10^4 K \). The activation energy for the reaction in J mol-1 is:
(Given R = 8.3 J K-1 mol-1)
1. \(4.0 \times 10^2 \)
2. \(4.0 \times 10^{-2} \)
3. \(8.3 \times 10^{-4} \)
4. \(8.3 \times 10^4 \)
1. | 0.16 M | 2. | 0.32 M |
3. | 0.08 M | 4. | 0.04 M |