- 1(current)
Q. No.A \(10~\mu\text F\) capacitor is connected to a \(210~\text V,50~\text{Hz}\) source as shown in the figure. The peak current in the circuit is nearly \((\pi = 3.14)\):
| 1. | \(0.93~\text A\) | 2. | \(1.20~\text A\) |
| 3. | \(0.35~\text A\) | 4. | \(0.58~\text A\) |
Subtopic: RMS & Average Values |
56%
Level 3: 35%-60%
NEET - 2024
Hints
The peak voltage of the AC source is equal to:
| 1. | \(1 / \sqrt{2}\) times the rms value of the AC source. |
| 2. | the value of voltage supplied to the circuit. |
| 3. | the rms value of the AC source. |
| 4. | \(\sqrt{2}\) times the rms value of the AC source. |
Subtopic: RMS & Average Values |
78%
Level 2: 60%+
NEET - 2022
Hints
A standard filament lamp consumes \(100~\text W\) when connected to \(200~\text V\) AC mains supply. The peak current through the bulb will be:
1. \(0.707~\text A\)
2. \(1~\text A\)
3. \(1.414~\text A\)
4. \(2~\text A\)
1. \(0.707~\text A\)
2. \(1~\text A\)
3. \(1.414~\text A\)
4. \(2~\text A\)
Subtopic: RMS & Average Values |
74%
Level 2: 60%+
NEET - 2022
Hints
A \(40~\mu\text F\) capacitor is connected to a \(200~\text V,\) \(50~\text{Hz}\) AC supply. The RMS value of the current in the circuit is, nearly:
| 1. | \(2.05~\text A\) | 2. | \(2.5~\text A\) |
| 3. | \(25.1~\text A\) | 4. | \(1.7~\text A\) |
Subtopic: RMS & Average Values |
71%
Level 2: 60%+
NEET - 2020
Hints
Links
In an AC circuit, an alternating voltage \(\varepsilon=200 \sqrt{2} \sin (100 t)~\text{V}\) is connected to a capacitor of capacity \(1~\mu \text{F}.\) The RMS value of the current in the circuit is:
| 1. | \(100~\text{mA}\) | 2. | \(200~\text{mA}\) |
| 3. | \(20~\text{mA}\) | 4. | \(10~\text{mA}\) |
Subtopic: RMS & Average Values | Different Types of AC Circuits |
78%
Level 2: 60%+
AIPMT - 2011
Hints
Links
The rms value of the potential difference \(V\) shown in the figure is:
| 1. | \(\dfrac{V_{0}}{\sqrt{3}}\) | 2. | \(V_{0}\) |
| 3. | \(\dfrac{V_{0}}{\sqrt{2}}\) | 4. | \(\dfrac{V_{0}}{2}\) |
Subtopic: RMS & Average Values |
74%
Level 2: 60%+
AIPMT - 2011
Hints
Links
In an AC circuit, the emf (e) and the current (I) at any instant are given respectively by
e = E0sint
I = I0sin
The average power in the circuit over one cycle of AC is:
1.
2.
3.
4.
Subtopic: RMS & Average Values |
83%
Level 1: 80%+
AIPMT - 2008
Hints
- 1(current)
Q. No.
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