In the absence of dissipative force, the time period \((T)\) of a simple pendulum (performing oscillations of small amplitude) is: 
1. \(2 \pi \sqrt{\frac{l}{g} } \)
2. \(2 \pi \sqrt{\frac{g}{l}} \)
\(\frac{1}{2} \pi \sqrt{\frac{l}{g}}\)
4. \(\frac{1}{2 \pi} \sqrt{\frac{g}{l}}\)
Subtopic:  Simple Harmonic Motion |
 96%
Level 1: 80%+
Please attempt this question first.
Hints
Please attempt this question first.

The displacement of the particle varies with time according to the relation.

y=asinωt+bcosωt, then

1. The motion is oscillating but not SHM

2. The motion is SHM with amplitude a+b

3. The motion is SHM with amplitude a2+b2

4. The motion is SHM with amplitude a2+b2

Subtopic:  Simple Harmonic Motion |
 95%
Level 1: 80%+
Hints

When two displacements represented by y1=asin(ωt) and y2=bcos(ωt) are superimposed,the motion is -

(1) not a simple harmonic

(2) simple harmonic with amplitude a/b

(3) simple harmonic with amplitude a2+b2

(4) simple harmonic with amplitude (a+b)/2

Subtopic:  Simple Harmonic Motion |
 94%
Level 1: 80%+
NEET - 2015
Hints

Assume that a tunnel is dug along a chord of the earth, at a perpendicular distance (\(R/2\)) from the earth's center, where '\(R\)' is the radius of the Earth. The wall of the tunnel is frictionless. If a particle is released in this tunnel, it will execute a simple harmonic motion with a time period :
1. \(\frac{2 \pi R}{g} \)
2. \(\frac{\mathrm{g}}{2 \pi \mathrm{R}} \)
3. \(\frac{1}{2 \pi} \sqrt{\frac{g}{R}} \)
4. \(2 \pi \sqrt{\frac{R}{g}} \)

Subtopic:  Simple Harmonic Motion |
 93%
Level 1: 80%+
JEE
Please attempt this question first.
Hints
Please attempt this question first.

The motion of a particle is given by \(x=A\sin\omega t+B\cos\omega t\). The motion of the particle is:

1. not simple harmonic.
2. simple harmonic with amplitude \(A+B\).
3. simple harmonic with amplitude \((A+B)/2\).
4. simple harmonic with amplitude \(\sqrt{A^2+B^2}\).

Subtopic:  Simple Harmonic Motion |
 92%
Level 1: 80%+
Hints

A particle performing simple harmonic motion such that its amplitude is \(4 ~\text m\) and speed of the particle at the mean position is \(10 ~\text{m/s}.\) Find the distance of the particle from the mean position where velocity becomes \(5 ~\text{m/s}.\)
1. \(\sqrt{3}\text{ m}\)
2. \(2\sqrt{3}\text { m}\)
3. \(\frac{\sqrt{3}}{2} \text{ m}\)
4. \(\frac{1}{\sqrt{2}}\text{ m}\)
Subtopic:  Simple Harmonic Motion |
 92%
Level 1: 80%+
JEE
Please attempt this question first.
Hints
Please attempt this question first.

When two displacements are represented by \(y_1 = a \text{sin}(\omega t)\) and \(y_2 = b\text{cos}(\omega t)\) are superimposed, then the motion is:

1. not simple harmonic.
2. simple harmonic with amplitude \(\dfrac{a}{b}\).
3. simple harmonic with amplitude \(\sqrt{a^2+b^{2}}.\)
4. simple harmonic with amplitude \(\dfrac{a+b}{2}\).
Subtopic:  Simple Harmonic Motion |
 92%
Level 1: 80%+
NEET - 2015
Hints

When two displacements represented by y1=asin(ωt) and y2=bcos(ωt) are superimposed,the motion is -

1. not a simple harmonic

2. simple harmonic with amplitude a/b

3. simple harmonic with amplitude a2+b2

4. simple harmonic with amplitude (a+b)/2

Subtopic:  Simple Harmonic Motion |
 92%
Level 1: 80%+
NEET - 2015
Hints

The displacement equation of a particle is x=3sin2t+4cos2t The amplitude and maximum velocity will be respectively

(a)       5, 10       (b)         3, 2

c)         4, 2        (d)         3, 4

Subtopic:  Simple Harmonic Motion |
 92%
Level 1: 80%+
Hints

Which of the following statements is/are true for a simple harmonic oscillator?
a. Force acting is directly proportional to displacement from the mean position and opposite to it.
b. Motion is periodic.
c. Acceleration of the oscillator is constant.
d. The velocity is periodic.
Choose the correct option:
1. (a), (c)
2. (a), (b), (d)
3. (b), (d)
4. (d) only
Subtopic:  Simple Harmonic Motion |
 91%
Level 1: 80%+
Please attempt this question first.
Hints