Q. No.The least count of a screw gauge is given by:
1. \({\text {Pitch}}\over {\text { Number of divisions on circular scale }}\)
2. \({\text{One circular scale division}} \over {\text{Number of divisions on main scale}}\)
3. \({\text{Number of divisions on circular scale }}\over {\text{One main scale division}}\)
4. \({\text{One circular scale division}}\over {\text{Pitch}}\)
1. \({\text {Pitch}}\over {\text { Number of divisions on circular scale }}\)
2. \({\text{One circular scale division}} \over {\text{Number of divisions on main scale}}\)
3. \({\text{Number of divisions on circular scale }}\over {\text{One main scale division}}\)
4. \({\text{One circular scale division}}\over {\text{Pitch}}\)
Subtopic: Â Measurement & Measuring Devices |
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The diameter of a thin wire is measured by:
| 1. | Screw gauge | 2. | Spherometer |
| 3. | Spectrometer | 4. | Venturimeter |
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In a vernier calipers \(49\) main scale divisions are equal to \(50\) vernier scale divisions. If one main scale division is \(0.5 ~\text{mm},\) then the vernier constant is:
1. \(0.01~\text{mm}\)
2. \(0.1~\text{mm}\)
3. \(0.1~\text{cm}\)
4. \(0.01~\text{cm}\)
1. \(0.01~\text{mm}\)
2. \(0.1~\text{mm}\)
3. \(0.1~\text{cm}\)
4. \(0.01~\text{cm}\)
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What is the reading displayed on the micrometer screw gauge shown in the figure, given that its least count is \(0.01~ \text{mm} \text{?}\)
| 1. | \(6.41 ~\text{mm}\) | 2. | \(6.38~\text{mm}\) |
| 3. | \(6.26 ~\text{mm}\) | 4. | \(6.48~\text{mm}\) |
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One centimeter on the main scale of Vernier calliper is divided into ten equal parts. If 10 divisions of Vernier scale coincide with 8 small divisions of the main scale, the least count of the callipers is:
(1) 0.01 cm
(2) 0.02 cm
(3) 0.05 cm
(4) 0.07 cm
Subtopic: Â Measurement & Measuring Devices |
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A vernier calliper is designed such that \(10\) main scale divisions coincide with \(11\) vernier scale divisions. If one main scale division corresponds to \(5~\text{mm},\) the least count of the instrument is:
| 1. | \(\dfrac{1}{2}~\text{mm}\) | 2. | \(\dfrac{5}{12}~\text{mm}\) |
| 3. | \(\dfrac{5}{11}~\text{mm}\) | 4. | \(0.3~\text{mm}\) |
Subtopic: Â Measurement & Measuring Devices |
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Let main scale division be of \(1~ \text{mm}\) and 50 divisions of vernier scale coincide with 49 divisions of main scale.
The least count of instrument is:
1. \(0.01 \text{ mm}\)
2. \(0.1 \text{ mm}\)
3. \(0.02 \text{ mm}\)
4. \(0.002 \text{ mm}\)
The least count of instrument is:
1. \(0.01 \text{ mm}\)
2. \(0.1 \text{ mm}\)
3. \(0.02 \text{ mm}\)
4. \(0.002 \text{ mm}\)
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A student measured the diameter of a small steel ball using a screw gauge of least count \(0.001 \mathrm{~cm} \text {. }\)The main scale reading is \(5 \mathrm{~mm} \) and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of \(-0.004 \mathrm{~cm}\), the correct diameter of ball is:
1. \(0.521 \mathrm{~cm}\)
2. \(0.525 \mathrm{~cm}\)
3. \(0.529 \mathrm{~cm}\)
4. \(0.053 \mathrm{~cm}\)
1. \(0.521 \mathrm{~cm}\)
2. \(0.525 \mathrm{~cm}\)
3. \(0.529 \mathrm{~cm}\)
4. \(0.053 \mathrm{~cm}\)
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The side of a cube is measured by vernier calipers (\(20\) divisions of the vernier scale coincide with \(19\) divisions of the main scale, where \(1\) division of the main scale is \(1~\text{mm}\)). The main scale reads \(10~\text{mm}\) and the first division of the vernier scale coincides with the main scale. The side length of a cube is:
1. \(10.02\) mm
2. \(10.05\) mm
3. \(10.04\) mm
4. \(10.06\) mm
1. \(10.02\) mm
2. \(10.05\) mm
3. \(10.04\) mm
4. \(10.06\) mm
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A screw gauge has least count of \(10 ~\mu \mathrm{m}\) and its circular scale is divided into 100 equal divisions. One main scale division is:
1. \(0.5 \mathrm{~mm}\)
2. \(1 \mathrm{~mm}\)
3. \(0.5 \mathrm{~cm}\)
4. \(1 \mathrm{~cm}\)
1. \(0.5 \mathrm{~mm}\)
2. \(1 \mathrm{~mm}\)
3. \(0.5 \mathrm{~cm}\)
4. \(1 \mathrm{~cm}\)
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