Q. No.A temperature of \(100^{\circ}\text {F}\) (Fahrenheit scale) is equal to \(T~\text{K}\) (Kelvin scale). The value of \(T\) is:
1. \(310.9\)
2. \(37.8\)
3. \(100\)
4. \(122.4\)
The temperature of a body on Kelvin scale is found to be X K. When it is measured by a Fahrenheit thermometer, it is found to be X0F. Then X is
1. 301.25
2. 574.25
3. 313
4. 40
On a new scale of temperature (which is linear) and called the \(\text W\) scale, the freezing and boiling points of water are \(39^{\circ}\text{ W}\) and \(239^{\circ}\text{ W}\) respectively. What will be the temperature on the new scale, corresponding to a temperature of
1. \(78^{\circ}\text{ W}\)
2. \(117^{\circ}\text{ W}\)
3. \(200^{\circ}\text{ W}\)
4. \(139^{\circ}\text{ W}\)
At what temperature do both the Centigrade and Fahrenheit thermometers show the same reading
1. –20
2. –40
3. 42
4. 0
The temperature of substance increases by 27°C this increases is equal to (in kelvin)
1. 300 K
2. 2.46 K
3. 27 K
4. 7 K
The temperature of a substance increases by . On the Kelvin scale, this increase is equal to
1. 300 K
2. 2.46 K
3. 27 K
4. 7 K
In a new temperature scale, freezing point of water is given a value and boiling point of water is . Reading of new temperature scale for a temperature equal to is
1.
2.
3.
4.
The temperature of a body on the Kelvin scale is found to be \(x^\circ~\text K.\) When it is measured by a Fahrenheit thermometer, it is found to be \(x^\circ~\text F,\) then the value of \(x\) is:
1. \(40\)
2. \(313\)
3. \(574.25\)
4. \(301.25\)
The fundamental interval, that is the number of division between LFP & UFP on the two scales X and Y are 50 and 150 respectively. The ice point on both the scales is . If the temperature on the X-scale is , then what is the temperature on the Y-scale ?
Recently, the phenomenon of super conductivity has been observed at 73 K. This temperature is nearly equal to
1.
2.
3.
4.
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