Q. No.Two sound waves with wavelength \(5.0\text{ m}\) and \(5.5\text{ m}\) respectively, each propagates in gas with a velocity of \(330\text{ m/s}.\) We expect the following number of beats per second:
1. \(12\)
2. \(0\)
3. \(1\)
4. \(6\)
1. \(12\)
2. \(0\)
3. \(1\)
4. \(6\)
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A source of unknown frequency gives \(4\text{ beats/s}\) when sounded with a source of known frequency \(250\text{ Hz}.\) The second harmonic of the source of unknown frequency gives five beats per second when sounded with a source of frequency \(513\text{ Hz}.\) The unknown frequency is:
1. \(246\text{ Hz}\)
2. \(240\text{ Hz}\)
3. \(260\text{ Hz}\)
4. \(254\text{ Hz}\)
1. \(246\text{ Hz}\)
2. \(240\text{ Hz}\)
3. \(260\text{ Hz}\)
4. \(254\text{ Hz}\)
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Two tuning forks of frequencies \(n_1\) and \(n_2\) produce \(n\) beats per second. If \(n_2\) and \(n\) are known, \(n_1\) may be given by:
1. \(\frac{{n}_{2}}{n}{+}{n}_{2}\)
2. \(n_2n\)
3. \({n}_{2}\pm{n}\)
4. \(\frac{{n}_{2}}{n}{-}{n}_{2}\)
1. \(\frac{{n}_{2}}{n}{+}{n}_{2}\)
2. \(n_2n\)
3. \({n}_{2}\pm{n}\)
4. \(\frac{{n}_{2}}{n}{-}{n}_{2}\)
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A tuning fork, placed in a room, vibrates according to the equation: \(Y=(10^{-4}~\text m)\sin\Big({\large\frac{2\pi t}{0.01~\text s}}\Big)\) where \(Y\) is the displacement of the tip of a prong. The speed of sound in air is \(330~\text{m/s}.\)
If an additional tuning fork of frequency \(102~\text{Hz}\) is sounded together with this, then a beat frequency of:
If an additional tuning fork of frequency \(102~\text{Hz}\) is sounded together with this, then a beat frequency of:
| 1. | \(1~\text{Hz}\) will be heard. |
| 2. | \(2~\text{Hz}\) will be heard. |
| 3. | \(202~\text{Hz}\) will be heard. |
| 4. | \(101~\text{Hz}\) will be heard. |
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Two tuning forks are sounded together and beats are heard at a frequency of \(2~\text{Hz}.\) The frequency of one tuning fork is \(120~\text{Hz}.\) The frequency of the other can be:
1. \(122~\text{Hz}\)
2. \(121~\text{Hz}\)
3. \(119~\text{Hz}\)
4. \(116~\text{Hz}\)
1. \(122~\text{Hz}\)
2. \(121~\text{Hz}\)
3. \(119~\text{Hz}\)
4. \(116~\text{Hz}\)
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Two sources of sound vibrating at \(200~\text{Hz}\) and \(204~\text{Hz}\) are sounded together. The beat frequency heard is:
| 1. | \(202~\text{Hz}\) | 2. | \(404~\text{Hz}\) |
| 3. | \(4~\text{Hz}\) | 4. | \(2~\text{Hz}\) |
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When two tuning forks with nearly equal frequencies (say: \(100~\text{Hz}\) and \(102~\text{Hz}\)) are sounded together,
| 1. | Beats of frequency \(2~\text{Hz}\) are heard |
| 2. | Beats of frequency \(101~\text{Hz}\) are heard |
| 3. | Echo of frequency \(202~\text{Hz}\) is heard |
| 4. | Standing waves of frequency \(202~\text{Hz}\) are formed |
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The fundamental frequency of vibration of a wire fixed at both ends is \(120~\text{Hz}.\) The wire can also vibrate in harmonics. The possible frequencies are:
| 1. | \(60~\text{Hz},40~\text{Hz},30~\text{Hz},...\) |
| 2. | \(240~\text{Hz},360~\text{Hz},480~\text{Hz},...\) |
| 3. | \(240~\text{Hz},300~\text{Hz},360~\text{Hz},...\) |
| 4. | \(180~\text{Hz},240~\text{Hz},300~\text{Hz},...\) |
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Two violinists are playing together, but they are slightly out of tune with each other. If one violinist plays a note at \(883\text{ Hz}\) and the other plays at \(879\text{ Hz} ,\) what beat frequency will be heard?
| 1. | \(2\text{ Hz}\) | 2. | \(4\text{ Hz}\) |
| 3. | \(881\text{ Hz}\) | 4. | \(1762\text{ Hz}\) |
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In two similar wires of tensions \(16~\text{N}\) and \(T,\) \(3\) beats are heard. If the wire of tension \(16~\text{N}\) has a frequency of \(4~\text{Hz},\) then \(T\) is equal to:
| 1. | \(49~\text{N}\) | 2. | \(64~\text{N}\) |
| 3. | \(25~\text{N}\) | 4. | none of these |
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