Match List I with List II.
List I
(Conversion)
List II
(Number of Faraday required)
A. 1 mol of H2O to O2 I. 3F
B. 1 mol of MnO4 to Mn2+ II. 2F
C. 1.5 mol of Ca from molten CaCl2 III. 1F
D. 1 mol of FeO to Fe2O3 IV. 5F
Choose the correct answer from the options given below:
1. A - III, B - IV, C - I, D - II
2. A - II, B - III, C - I, D - IV
3. A - III, B - IV, C - II, D - I
4. A - II, B - IV, C - I, D - III
Subtopic:  Faraday’s Law of Electrolysis |
 64%
From NCERT
NEET - 2024
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Mass in grams of copper deposited by passing 9.6487 A current through a voltmeter containing copper sulphate for 100 seconds is(Given : Molar mass of Cu: 63gmol1 F = 96487 C) 

1. 0.315 g 
2. 31.5 g 
3. 0.0315 g 
4. 3.15 g 
Subtopic:  Faraday’s Law of Electrolysis |
 66%
From NCERT
NEET - 2024
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Given below are two statements:
Statement I: 2 F electricity is required for the oxidation of 1 mole H2O to O2.
Statement II: To get 40.0 g of Aluminium from molten Al2O3 required electricity is 4.44 F.

In the light of the above statements, choose the correct answer from the options given below:
1. Both Statement I and Statement II are true
2. Both Statement I and Statement II are false
3. Statement I is true but Statement II is false
4. Statement I is false but Statement II is true
Subtopic:  Faraday’s Law of Electrolysis |
 64%
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NEET - 2024
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From the following select the one which is not an example of corrosion:
1. Rusting of an iron object
2. Production of hydrogen by electrolysis of water
3. Tarnishing of silver
4. Development of green coating on copper and bronze ornaments
Subtopic:  Corrosion |
 83%
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NEET - 2024
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The standard cell potential of the following cell Zn|Zn2+(aq)Fe2+(aq)|Fe  is  0.32 V. Calculate the standard Gibbs energy change for the reaction:
Zn(s)+Fe2+(aq)Zn2+(aq)+Fe(s)

(Given : 1 F=96487Cmol1)

1. 61.75 kJ mol1
2. +5.006 kJ mol1
3. 5.006 kJ mol1
4. +61.75 kJ mol1
Subtopic:  Relation between Emf, G, Kc & pH |
 82%
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NEET - 2024
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Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R):
Assertion (A): In equation ΔrG=nFEcell , value ΔrG depends on n. 
Reason (R): Ecell is an intensive property and ΔrG  is an extensive property. 
In the light of the above statements choose the correct answer from the options given below: 
1. (A) is False but (R) is True. 
2. Both (A) and (R) are True and (R) is the correct explanation of (A)
3. Both (A) and (R) are True and (R) is not the correct explanation of (A)
4. (A) is True but (R) is False.
Subtopic:  Relation between Emf, G, Kc & pH |
 58%
From NCERT
NEET - 2023
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The conductivity of centimolar solution of KCl at 25°C is 0.0210 ohm–1 cm–1 and the resistance of the cell containing the solution at 25°C is 60 ohm. The value of the cell constant is: 
1. 3.34 cm–1 2. 1.34 cm–1
3. 3.28 cm–1 4. 1.26 cm–1
Subtopic:  Conductance & Conductivity |
 79%
From NCERT
NEET - 2023
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The molar conductance of an electrolyte increases with dilution according to the equation: 
Λm=ΛmAc
Consider the following four statements:
A: This equation applies to both strong and weak electrolytes.
B: The value of the constant A depends upon the nature of the solvent. 
C: The value of constant A is the same for both BaCl2 and MgSO4
D: The value of constant A is the same for both BaCl2 and Mg(OH)2
Which of the above statements are correct? 
1. (A) and (B) only  2. (A), (B), and (C) only 
3. (B) and (C) only  4. (B) and (D) only 
Subtopic:  Conductance & Conductivity |
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NEET - 2023
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The correct value of cell potential in volt for the reaction that occurs when the following two half cells are connected, is:
Fe(aq)2++2eFe(s),E=0.44 V
Cr2O72(aq)+14H++6e2Cr3++7H2O,
E=+1.33 V
1. +1.77 V
2. +2.65 V 
3. +0.01 V 
4. +0.89 V
Subtopic:  Electrode & Electrode Potential |
 73%
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NEET - 2023
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The molar conductance of a solution, given its conductivity (0.248 S m–1) and concentration (0.2 mol m–3) is:
1. 0.124 S cm2 mol–1
2. 1.24 S mmol–1
3. 124 S cm2 mol–1
4. 124 S m2 mol–1
Subtopic:  Conductance & Conductivity |
From NCERT
NEET - 2023
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