- 1(current)
Q. No.At a pressure of \(5 \times 10^5\) bar, the densities of diamond and graphite are 3 g/cc and 2 g/cc, respectively, at a certain temperature T. Calculate the value of \(\Delta U-\Delta H \mathrm{}\) for the conversion of 1 mole of graphite to 1 mole of diamond at a temperature T.
1. \(100 \mathrm{~kJ} / \mathrm{mol}\)
2. \(50 \mathrm{~kJ} / \mathrm{mol}\)
3. \(-~100 \mathrm{~kJ} / \mathrm{mol}\)
4. \(-~50 \mathrm{~kJ} / \mathrm{mol}\)
1. \(100 \mathrm{~kJ} / \mathrm{mol}\)
2. \(50 \mathrm{~kJ} / \mathrm{mol}\)
3. \(-~100 \mathrm{~kJ} / \mathrm{mol}\)
4. \(-~50 \mathrm{~kJ} / \mathrm{mol}\)
Subtopic: Enthalpy & Internal energy |
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.
Based on the reactions, ascertain the valid algebraic relationship:
| 1. | x = y | 2. | x = 2y |
| 3. | x > y | 4. | x < y |
Subtopic: Enthalpy & Internal energy |
From NCERT
To view explanation, please take trial in the course.
NEET 2021 - Achiever Batch - Aryan Raj Singh
Hints
To view explanation, please take trial in the course.
NEET 2021 - Achiever Batch - Aryan Raj Singh
| Assertion (A): | The heat absorbed during the isothermal expansion of an ideal gas against a vacuum is zero. |
| Reason (R): | The volume occupied by the molecules of an ideal gas is zero. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
Subtopic: Enthalpy & Internal energy |
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.
- 1(current)
Q. No.
© 2025 GoodEd Technologies Pvt. Ltd.