Q. No.If the number of turns, area, and current through a coil are given by \(n\), \(A\) and \(i\) respectively then its magnetic moment will be:
1. \(niA\)
2. \(n^{2}iA\)
3. \(niA^{2}\)
4. \(\frac{ni}{\sqrt{A}}\)
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For a circular coil of radius \(5\) cm having \(100\) turns and carrying a current of \(2.0\) A, the magnetic moment is:
1. \(12.95\) A-m2
2. \(25.97\) A-m2
3. \(1.6\) A-m2
4. \(24.79\) A-m2
| 1. | \(\left({{i}_{0}{\pi}{R}_{0}^{2}}\right)\sqrt{2} \) | 2. | zero |
| 3. | \({i}_{0}\times{2}{\pi}{R}_{0}^{2} \) | 4. | \({i}_{0}\left({{4}{\pi}{R}_{0}}\right) \) |
Magnetic dipole moment is a
1. Scalar quantity
2. Vector quantity
3. Constant for all magnets
4. Temperature independent quantity
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1. \(\dfrac{3}{2}q\omega r^2\)
2. \(\dfrac{1}{2}q\omega r^2\)
3. \(q\omega r^2\)
4. \(\dfrac{4}{3}q\omega r^2\)
1. \(\dfrac{{IL}^{2}}{{4}\mathit{\pi}}\)
2. \(\dfrac{IL}{{4}\mathit{\pi}}\)
3. \(\dfrac{{I}^{2}L}{{4}\mathit{\pi}}\)
4. \(\dfrac{{I}^{2}{L}^{2}}{{4}\mathit{\pi}}\)
A closely wound solenoid of \(800\) turns and area of cross-section \(2.5 \times10^{-4}~\text{m}^2\) carries a current of \(3.0~\text{A}\). If the solenoid acts like a bar magnet, then what is its associated magnetic moment?
1. \(0.6~\text{J/T}\)
2. \(0.07~\text{J/T}\)
3. \(0.3~\text{J/T}\)
4. \(0.8~\text{J/T}\)
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A \(100\) turn closely wound circular coil of radius \(10~\text{cm}\) carries a current of \(3.2~\text{A}.\) The magnetic moment of this coil is:
1. \(20~\text{A-m}^2\)
2. \(10~\text{A-m}^2\)
3. \(30~\text{A-m}^2\)
4. \(15~\text{A-m}^2\)
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| 1. | \(2 Ia^2\) | 2. | \(\sqrt{3} I a^2\) |
| 3. | \(Ia^2\) | 4. | \(3 Ia^2\) |
| 1. | \(N\pi eR\) | 2. | \(\dfrac{e\pi R^2}{N }\) |
| 3. | \(Ne\pi R^2\) | 4. | \(\dfrac{e\pi R^2}{N}\) |
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