Q. No.Cl- = 71 S cm2mol–1, then the limiting molar conductivity of CaCl2 is:
1. 341 S cm2mol–1
2. 261 S cm2mol–1
3. 126 S cm2mol–1
4. 431 S cm2mol–1
| Column I | Column II | ||
| (A) | \( \wedge_m\) | (i) | \(l/A\) |
| (B) | \(G^*\) | (ii) | \(\rho l/A \) |
| (C) | \(\kappa\) | (iii) | \(\kappa /C\) |
| (D) | R | (iv) | \(\frac{G^*}{R}\) |
1. (A) →(i), (B)→(iii), (C) →(ii), (D)→ (iv)
2. (A) →(iii), (B)→(i), (C) →(iv), (D)→ (ii)
3. (A) →(ii), (B)→(iv), (C) →(iii), (D)→ (i)
4. (A) →(iv), (B)→(ii), (C) →(i), (D)→ (iii)
| 1. | \(124.66 ~ \text {Scm}^2/ \text {mol} \) | 2. | \(135.66 ~ \text {Scm}^2/ \text {mol} \) |
| 3. | \(198.20 ~ \text {Scm}^2/ \text {mol} \) | 4. | \(175.78 ~ \text {Scm}^2/ \text {mol} \) |
Equivalent conductances of NaCl, HCl and C2H5COONa at infinite dilution are 126.45, 426.16 and 91 . The equivalent conductance of C2H5COOH is :
1. 201.28
2. 390.71
3. 698.28
4. 540.48
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
1. 1.29 cm–1
2. 12.9 cm–1
3. 129 cm–1
4. 1290 cm–1
Match the terms given in Column I with the units given in Column II.
|
Column I |
Column II |
||
| A. | 1. |
S cm–1 |
|
| B. | Ecell | 2. | m–1 |
| C. | κ | 3. | S cm2 mol–1 |
| D. | G* | 4. | V |
Codes:
| Options: | A | B | C | D |
| 1. | 3 | 4 | 1 | 2 |
| 2. | 1 | 2 | 3 | 5 |
| 3. | 5 | 4 | 3 | 2 |
| 4. | 4 | 5 | 3 | 2 |
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
1. \(124~ \Omega ^{-1} ~cm^2~mol^{-1}\)
2. \(204~ \Omega ^{-1} ~cm^2~mol^{-1}\)
3. \(101~ \Omega ^{-1} ~cm^2~mol^{-1}\)
4. \(300~ \Omega ^{-1} ~cm^2~mol^{-1}\)
The correct choice among the given regarding formula of Conductivity is -
(a)
(b)
(c)
(d)
1. (a, b)
2. (b, c)
3. (c, d)
4. (a, d)
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
The molar conductivity of a solution of AgNO3 (considering the given data for this solution) at 298 K is:
(a) Concentration: 0.5 mol/dm3
(b) Electrolytic conductivity: 5.76×10–3 S cm–1
| 1. | 2.88 S cm2/mol | 2. | 11.52 S cm2/mol |
| 3. | 0.086 S cm2/mol | 4. | 28.8 S cm2/mol |
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
1. 203
2. 421
3. 143
4. 303
© 2026 GoodEd Technologies Pvt. Ltd.