Q. No.1. \(1.0~\text m\)
2. \(1.5~\text m\)
3. \(1.65~\text m\)
4. \(1.75~\text m\)
1. \(1000\) m/s
2. \(2000\) m/s
3. \(500\) m/s
4. \(4000\) m/s
The temperature at which the velocity of sound in air becomes double its velocity at \(0^\circ \text{C}\) is:
| 1. | \(435^\circ \text{C}\) | 2. | \(694^\circ \text{C}\) |
| 3. | \(781^\circ \text{C}\) | 4. | \(819^\circ \text{C}\) |
| (a) | directly on density of the medium. |
| (b) | square of Bulk modulus of the medium. |
| (c) | inversly on the square root of density. |
| (d) | directly on the square root of bulk modulus of the medium. |
Choose the correct option:
| 1. | (a), (c) | 2. | (a), (b), (c) |
| 3. | (b), (d) | 4. | (c), (d) |
\(y(x,t)=0.06\sin\Big(\dfrac{2\pi}{3}x\Big)\cos(120\pi t)\)
where \(x\) and \(y\) are in meter and \(t\) in second. The length of the string is \(1.5~\text{m}\) and its mass is \(3\times10^{-2}~\text{kg}.\) The tension in the string is:
1. \(540~\text{N}\)
2. \(648~\text{N}\)
3. \(200~\text{N}\)
4. \(425~\text{N}\)
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The speed of sound in air at NTP is \(720 ~\text{m/s}.\) If the pressure is increased to \(9\) times the atmospheric pressure, then the speed of sound at the same temperature will be:
1. \(720 ~\text{m/s}\)
2. \(960 ~\text{m/s}\)
3. \(320\sqrt{3} ~\text{m/s}\)
4. \(320 ~\text{m/s}\)
The frequency of vibration of a tuning fork is \(400~\text{Hz}.\) If the velocity of sound in air is \(330~\text{m/s},\) then how far the sound has traversed while the tuning fork completes \(40\) vibrations?
1. \(24~\text m \)
2. \(57~\text m \)
3. \(42~\text m \)
4. \(33~\text m \)
A tuning fork has a frequency of \(200\) Hz. If the velocity of sound in air is \(330\) m/s, then how far the sound has traversed while the tuning fork completes \(20\) vibrations?
| 1. | \(11~\text{m}\) | 2. | \(22~\text{m}\) |
| 3. | \(33~\text{m}\) | 4. | \(44~\text{m}\) |
A hospital uses an ultrasonic scanner to locate tumors in a tissue. What is the wavelength of sound in the tissue in which the speed of sound is \(1.7~\text{km/s}\)? The operating frequency of the scanner is \(4.2~\text{MHz}\).
| 1. | \(3.0 \times10^{-4}~\text{m}\) | 2. | \(4.0 \times10^{-4}~\text{m}\) |
| 3. | \(3.5 \times10^{-4}~\text{m}\) | 4. | \(2.0 \times10^{-4}~\text{m}\) |
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1. \(\lambda \)
2. \(\dfrac{\lambda}{2} \)
3. \(2 \lambda \)
4. \(4 \lambda\)
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