Q. No.Match the items in Column I with relevant items in Column II.
|
Column I |
Column II |
||
| A. |
Ions having a positive charge |
1. |
+7 |
| B. |
The sum of oxidation number of all atoms in a neutral molecule |
2. |
–1 |
| C. |
Oxidation number of hydrogen ion. (H+) |
3. |
+1 |
| D. |
Oxidation number of fluorine in NaF |
4. |
0 |
| E. |
Ions having a negative charge |
5. |
Cation |
| 6. |
Anion |
Codes:
| Options: | A | B | C | D | E |
| 1. | 5 | 4 | 3 | 2 | 6 |
| 2. | 1 | 2 | 3 | 5 | 4 |
| 3. | 5 | 4 | 3 | 2 | 1 |
| 4. | 4 | 5 | 3 | 2 | 1 |
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1. -2, -5, -1, 0
2. +5, +7, -1, 0
3. +2, +5, +1, 0
4. -1, +1, 0, +1
| Column I (Compound) |
Column II (Oxidation states of Fe) |
||
| (A) | \(K_3[Fe(OH)_6]\) | (i) | +8/3 |
| (B) | \(K_2[FeO_4]\) | (ii) | +2 |
| (C) | \(FeSO_4(NH_4)_2SO_4.6H_2O\) | (iii) | +3 |
| (D) | \(Fe_3O_4\) | (iv) | +6 |
1. (A) →(iii), (B)→(i), (C) →(ii), (D)→ (iv)
2. (A) →(iii), (B)→(iv), (C) →(ii), (D)→ (i)
3. (A) →(i), (B)→(iii), (C) →(ii), (D)→ (iv)
4. (A) →(iv), (B)→(ii), (C) →(i), (D)→ (iii)
(O.S = oxidation state)
| Column I | Column II |
| a. Fe O.S in Fe2O3 | i. +2 |
| b. Mn O.S in MnO2 | ii. +3 |
| c. Mn O.S in MnO | iii. +4 |
1. a=i; b=ii; c=iii
2. a=ii; b=iii; c=i
3. a=iii; b=ii; c=i
4. a=ii; b=i; c=iii
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1. 1.5
2. 2.5
3. 3.0
4. 2.0
A B C
The oxidation state of sulfur in the given equation is A, B, and C.
A, B, and C are respectively:
1. 0, -2, +2
2. -2, 0, -2
3. 0, +2, -2
4. -2, -2, +2
Among the following compounds, which one is a transition metal with an oxidation number of zero?
1. \(\mathrm{\left[{Fe}\left({H}_2 {O}\right)_3\right]({OH})_2}\)
2. \(\mathrm{\left[{Co}\left({NH}_3\right)_6\right] {Cl}_2}\)
3. \(\mathrm{\left[{Ni}({CO})_4\right]}\)
4. \(\mathrm{\left[{Pt}\left({C}_2 {H}_4\right) {Cl}_3\right]}\)
| 1. | For ions, the oxidation number is equal to the charge of the ion. |
| 2. | Oxygen always has an oxidation number of -2 in all its compounds. |
| 3. | Fluorine has an oxidation number of -1 in all its compounds. |
| 4. | Hydrogen usually has an oxidation number of +1, except in binary hydrides of alkali and alkaline earth metals, where it is -1. |
| 1. | Three (6) | 2. | Zero (0) |
| 3. | Two (2) | 4. | Three (3) |
| Assertion (A): | HNO3 acts as an oxidizing agent. |
| Reason (R): |
The oxidation state of nitrogen in HNO₃ is +5, which cannot increase further. Thus, the oxidation state of nitrogen in HNO₃ can only decrease. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | Both (A) and (R) are False. |
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