Q. No.Match the items of column I with items of column II.
|
Column I |
Column II |
|
a. |
i. 1,3,5,7-Octatetraene |
|
b. |
ii. 4-Ethyl-2,6-dimethyl-dec-4-ene |
|
c. |
iii. 2,8-Dimethyl-3, 6-decadiene |
|
d. CH2=C(CH2CH2CH3)2 |
iv. 2-n-Propylpent-1-ene |
1. a= iii; b = iv; c= ii; d = i
2. a = i; b = iii; c = ii; d = iv
3. a = ii; b = i; c = iv; d = iii
4. a = iv; b = i; c = ii; d = iii
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1. 3-Ethyl-4-methylheptane
2. 3-Ethyl-4, 7-dimethynonane
3. 3-Methyl-7-ethydecane
4. 3,4-Diethyl-5, 7-dimethylnonane
1. 30
2. 60
3. 120
4. 90
1. 2 - Phenyl - 1 - butene
2. 1, 1 - Diphenyl - 1 - propene
3. 1 - Phenyl - 2 - butene
4. 3 - Phenyl - 1 - butene
| 1. | 1.0 | 2. | 2.0 |
| 3. | 6.0 | 4. | Infinite |
The number of hydrogen atoms attached to primary (1°), secondary (2°), and tertiary (3°) carbons in the given organic compound are:
1. 18, 4, 0
2. 18, 6, 0
3. 20, 6, 2
4. 18, 4, 2
Geometrical isomerism is not shown by:
1. 1,1-Dichloro-1-pentene
2. 1,2-Dichloro-1-pentene
3. 1,3-Dichloro-2-pentene
4. 1,4-Dichloro-2-pentene
Match the items of Column I with items of Column II.
|
Column I |
Column II |
||
| a. |
(CH3)3 CCH2C(CH3)3 |
i. | 3,3-Di-tert-butyl-2,2,4,4-tetramethylpentane |
| b. |
(CH3)2 C(C2H5)2 |
ii. |
2,2,4,4-Tetramethylpentane |
| c. | Tetra – tert-butyl methane | iii. |
3,3-Dimethylpentane |
| 1. | a = i; b = ii; c = iii | 2. | a = iii; b = ii; c = i |
| 3. | a = ii; b = iii; c = i | 4. | a = iii; b = i; c = ii |
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| 1. | 1, 2-Dichloro-1-pentene | 2. | 1, 3-Dichloro-2-pentene |
| 3. | 1, 1-Dichloro-1-pentene | 4. | 1, 4-Dichloro-2-pentene |
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