Match the species in Column I with the type of hybrid orbitals in Column II.

Column I

Column II

A.

SF4

1.

sp3d2

B.

IF5

2.

d2sp3

C.

NO2+

3.

sp3d

D.

NH4+

4.

sp3

5.

sp

Codes:

Options:  A   B   C   D 
1. 3 1 5 4
2. 1 2 3 5
3. 5 4 3 2
4. 4 5 3 2
Subtopic:  Hybridisation | V.S.E.P.R & V.B.T |
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Match the species in Column I with the shape in Column II.

Column I

Column II

A.

H3O+

1.

Linear

B.

HCCH

2.

Angular

C.

ClO2-

3.

Tetrahedral

D.

NH4+

4.

Trigonal bipyramidal

5.

Pyramidal

Codes:

Options:  A   B   C   D 
1. 5  1  2  3
2. 1  2  3  5
3. 5  4  3  2
4. 4  5  3  2

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In a chemical change from PCl3  PCl5 the hybrid state of P changes from :

1. sp2 to sp3

2. sp3 to sp2

3. sp3 to sp3d

4. sp3 to dsp

Subtopic:  Hybridisation | V.S.E.P.R & V.B.T |
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Match the column :

 

I

 

II

(P)

BH4-

(I)

Linear; 2 bond pair and 3 lone pair

(Q)

ICl2+

(II)

Tetrahedral, 4 bond pair and no lone pair

(R)

ICl2-

(III)

Tetrahedral; 3 bond pair and 1 lone pair

(S)

ICl4-

(IV)

V shaped; 2 bond pair and 2 lone pair

 

 

(V)

Square planar; 4 bond pair and 2 lone pair

 

 

(VI)

Square planar; 4 bond pair and no lone pair

1. P = II, Q = IV, R = III, S = VI

2.  P = II, Q = IV, R = I, S = V

3.  P = II, Q = I, R = V, S = VI  

4.  P = II, Q = I, R = III, S = IV

Subtopic:  Hybridisation | V.S.E.P.R & V.B.T |
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Choose the correct option based on matching.
Hybridization  Shape 
A.  \(s p^3\) I.  Octahedral 
B.  \(s p^3 d\) II.  Tetrahedral 
C.  \(s p^2\) III.  Trigonal bipyramidal 
D.  \(s p^3 d^2\) IV.  Trigonal planar 

1. A (I); B (II); C (III); D (IV)
2. A (II); B (III); C (IV); D (I)
3. A (II); B (III); C (I); D (IV) 
4. A (III); B (II); C (IV); D (I)
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Which of the following pairs does not represent a proper relationship between the two items?

1. \(sp^3\) and \(109.5^\circ\)
2. Trigonal planar and \(120^\circ\)
3. \(sp\) and \(180^\circ\)
4. Square planar and \(120^\circ\)
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Match List-I with List-II:
List-I
(Species)
List-II
(Hybrid orbitals/​Hybridization)
(a)  \(\mathrm{SF}_4\) (i) \(s p^3 d^2\)
(b) \(\mathrm{IF}_5\) (ii) \(d^2 s p^3\)
(c) \(\mathrm{NO}_2^{\oplus}\) (iii) \(\mathrm{sp}^3 \mathrm{~d}\)
(d) \(\mathrm{NH}_4^{\oplus}\) (iv) \(\mathrm{sp}^3\)
(v) \(\text { sp }\)
Choose the correct answer from the options given below:
1. (a)–(ii), (b)–(i), (c)-(iv) and (d)–(v)
2. (a)–(iv), (b)–(iii), (c)-(ii) and (d)–(v)
3. (a)–(i), (b)–(ii), (c)-(v) and (d)–(iii)
4. (a)–(iii), (b)–(i), (c)-(v) and (d)–(iv)
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Hybridization of C1 and C2 in the structure given below are:
     
1.  C1=sp2,C2=sp3
2.  C1=sp3,C2=sp2
3.  C1=sp3,C2=sp3
4. C1=sp2,C2=sp2
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The hybridization of orbitals of N atom in NO3, NO2+ and  NH4+ are respectively: 

1. sp, sp2, sp3

2. sp2, sp, sp3

3. sp, sp3, sp2

4. sp2, sp3, sp

Subtopic:  Hybridisation | V.S.E.P.R & V.B.T |
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The number of π-bonds in the formula given below, NC—CH=CH—CN are:

1. 5 2. 4
3. 3 4. 2
Subtopic:  Hybridisation |
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