Match the species in Column I with the type of hybrid orbitals in Column II.
|
Column I |
Column II |
||
| A. |
SF4 |
1. |
sp3d2 |
| B. |
IF5 |
2. |
d2sp3 |
| C. |
NO2+ |
3. |
sp3d |
| D. |
NH4+ |
4. |
sp3 |
| 5. |
sp |
Codes:
| Options: | A | B | C | D |
| 1. | 3 | 1 | 5 | 4 |
| 2. | 1 | 2 | 3 | 5 |
| 3. | 5 | 4 | 3 | 2 |
| 4. | 4 | 5 | 3 | 2 |

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Match the species in Column I with the shape in Column II.
|
Column I |
Column II |
||
| A. |
H3O+ |
1. |
Linear |
| B. |
HCCH |
2. |
Angular |
| C. |
ClO2- |
3. |
Tetrahedral |
| D. |
NH4+ |
4. |
Trigonal bipyramidal |
| 5. |
Pyramidal |
Codes:
| Options: | A | B | C | D |
| 1. | 5 | 1 | 2 | 3 |
| 2. | 1 | 2 | 3 | 5 |
| 3. | 5 | 4 | 3 | 2 |
| 4. | 4 | 5 | 3 | 2 |

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In a chemical change from PCl3 PCl5 the hybrid state of P changes from :
1. sp2 to sp3
2. sp3 to sp2
3. sp3 to sp3d
4. sp3 to dsp

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Match the column :
|
|
I |
|
II |
|
(P) |
(I) |
Linear; 2 bond pair and 3 lone pair |
|
|
(Q) |
(II) |
Tetrahedral, 4 bond pair and no lone pair |
|
|
(R) |
(III) |
Tetrahedral; 3 bond pair and 1 lone pair |
|
|
(S) |
(IV) |
V shaped; 2 bond pair and 2 lone pair |
|
|
|
|
(V) |
Square planar; 4 bond pair and 2 lone pair |
|
|
|
(VI) |
Square planar; 4 bond pair and no lone pair |
1. P = II, Q = IV, R = III, S = VI
2. P = II, Q = IV, R = I, S = V
3. P = II, Q = I, R = V, S = VI
4. P = II, Q = I, R = III, S = IV

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| Hybridization | Shape | ||
| A. | \(s p^3\) | I. | Octahedral |
| B. | \(s p^3 d\) | II. | Tetrahedral |
| C. | \(s p^2\) | III. | Trigonal bipyramidal |
| D. | \(s p^3 d^2\) | IV. | Trigonal planar |
| List-I (Species) |
List-II (Hybrid orbitals/Hybridization) |
||
| (a) | \(\mathrm{SF}_4\) | (i) | \(s p^3 d^2\) |
| (b) | \(\mathrm{IF}_5\) | (ii) | \(d^2 s p^3\) |
| (c) | \(\mathrm{NO}_2^{\oplus}\) | (iii) | \(\mathrm{sp}^3 \mathrm{~d}\) |
| (d) | \(\mathrm{NH}_4^{\oplus}\) | (iv) | \(\mathrm{sp}^3\) |
| (v) | \(\text { sp }\) |

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The hybridization of orbitals of N atom in NO3−, NO2+ and NH4+ are respectively:
1. sp, sp2, sp3
2. sp2, sp, sp3
3. sp, sp3, sp2
4. sp2, sp3, sp
The number of π-bonds in the formula given below, NC—CH=CH—CN are:
| 1. | 5 | 2. | 4 |
| 3. | 3 | 4. | 2 |