The isoelectronic pair of ions is
1. Sn2+ and V3+
2. Mn2+ and Fe3+
3. Mn3+ and Fe2+
4. Ni3+ and Fe2+
The compound among NH3, BCl3, Cl2 and N2, that does not satisfy the octet rule is:
1. NH3
2. BCl3
3. Cl2
4. N2
The largest bond angle at the central atom among the following is:
1. CO2
2. POCl3
3. BCl3
4. SO3
The bond order for a species with the configuration will be:
1. 1
2.
3. Zero
4. \(\frac{3}{2}\)

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Match the species in Column I with the 5 types of hybrid orbitals given in Column II:
| Column I | Column II | ||
| 1 | \(SF_4\) | (a) | \(sp^3d^2\) |
| 2 | \(IF_5\) | (b) | \(d^2sp^3\) |
| 3 | \(NO^+_2\) | (c) | \(sp^3d\) |
| 4 | \(NH^+_4\) | (d) | \(sp^3\) |
| (e) | \(sp\) |
1. (1) → (a), (2) → (b), (3) → (e), (4) → (d)
2. (1) → (c), (2) → (a), (3) → (e), (4) → (d)
3. (1) → (d), (2) → (a), (3) → (e), (4) → (c)
4. (1) → (e), (2) → (b), (3) → (c), (4) → (d)

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Identify the species in which the central atom exhibits \(sp^2\) hybridization:
1. \(PH_3\)
2. \(NH_3\)
3. \(CH_3^+\)
4. \(SbH_3\)

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The number of sigma () and pi () bonds in pent-2-en-4-yne is:
1. 13 bonds and no bond
2. 10 bonds and 3 bonds
3. 8 bonds and 5 bonds
4. 11 bonds and 2 bonds

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Match the column :
|
|
I |
|
II |
|
(P) |
(I) |
Linear; 2 bond pair and 3 lone pair |
|
|
(Q) |
(II) |
Tetrahedral, 4 bond pair and no lone pair |
|
|
(R) |
(III) |
Tetrahedral; 3 bond pair and 1 lone pair |
|
|
(S) |
(IV) |
V shaped; 2 bond pair and 2 lone pair |
|
|
|
|
(V) |
Square planar; 4 bond pair and 2 lone pair |
|
|
|
(VI) |
Square planar; 4 bond pair and no lone pair |
1. P = II, Q = IV, R = III, S = VI
2. P = II, Q = IV, R = I, S = V
3. P = II, Q = I, R = V, S = VI
4. P = II, Q = I, R = III, S = IV

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In a chemical change from PCl3 PCl5 the hybrid state of P changes from :
1. sp2 to sp3
2. sp3 to sp2
3. sp3 to sp3d
4. sp3 to dsp

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