Which of the following is paramagnetic?

1.  CO

2.  O2-

3.  CN-

4.  NO+

Subtopic:  M.O.T |
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The isoelectronic pair of ions is                             

1. Sn2+ and V3+

2. Mn2+ and Fe3+

3. Mn3+ and Fe2+

4. Ni3+ and Fe2+

Subtopic:  Octate, Isoelectronic Species, Lewis Structure & Formal Charge |
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The compound among NH3, BCl3, Cl2 and N2, that does not satisfy the octet rule is:

1. NH3

2. BCl3

3. Cl2

4. N2

Subtopic:  Octate, Isoelectronic Species, Lewis Structure & Formal Charge |
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The largest bond angle at the central atom among the following  is:

1. CO2

2. POCl3

3. BCl3

4. SO3

Subtopic:  V.S.E.P.R & V.B.T |
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The bond order for a species with the configuration σ1s2σ*1s2σ2s2σ*2s2σρ1x will be:

1.  1

2.  12

3.  Zero

4.  \(\frac{3}{2}\)

Subtopic:  M.O.T |
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Match the species in Column I with the 5 types of hybrid orbitals given  in Column II:

Column I Column II
1 \(SF_4\) (a) \(sp^3d^2\)
2 \(IF_5\) (b) \(d^2sp^3\)
3 \(NO^+_2\) (c) \(sp^3d\)
4 \(NH^+_4\) (d) \(sp^3\)
(e) \(sp\)

1. (1) → (a), (2) → (b), (3) → (e), (4) → (d)

2. (1) → (c), (2) → (a), (3) → (e), (4) → (d)

3. (1) → (d), (2) → (a), (3) → (e), (4) → (c)

4. (1) → (e), (2) → (b), (3) → (c), (4) → (d)

Subtopic:  Hybridisation |
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Identify the species in which the central atom exhibits \(sp^2\) hybridization:

1. \(PH_3\)
2. \(NH_3\)
3. \(CH_3^+\)
4. \(SbH_3\)

Subtopic:  Hybridisation |
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The number of sigma (σ) and pi (π) bonds in pent-2-en-4-yne is:

1. 13 σ bonds and no π bond

2. 10 σ bonds and 3 π bonds

3. 8 σ bonds and 5 π bonds

4. 11 σ bonds and 2 π bonds

Subtopic:  Types of Chemical Bond |
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Level 1: 80%+
NEET - 2019

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Match the column :

 

I

 

II

(P)

BH4-

(I)

Linear; 2 bond pair and 3 lone pair

(Q)

ICl2+

(II)

Tetrahedral, 4 bond pair and no lone pair

(R)

ICl2-

(III)

Tetrahedral; 3 bond pair and 1 lone pair

(S)

ICl4-

(IV)

V shaped; 2 bond pair and 2 lone pair

 

 

(V)

Square planar; 4 bond pair and 2 lone pair

 

 

(VI)

Square planar; 4 bond pair and no lone pair

1. P = II, Q = IV, R = III, S = VI

2.  P = II, Q = IV, R = I, S = V

3.  P = II, Q = I, R = V, S = VI  

4.  P = II, Q = I, R = III, S = IV

Subtopic:  Hybridisation | V.S.E.P.R & V.B.T |
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In a chemical change from PCl3  PCl5 the hybrid state of P changes from :

1. sp2 to sp3

2. sp3 to sp2

3. sp3 to sp3d

4. sp3 to dsp

Subtopic:  Hybridisation | V.S.E.P.R & V.B.T |
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