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Q. No.An electron , a proton and an alpha particle having the same kinetic energy are moving in circular orbits of radii \(r_e,r_p,r_\alpha\) respectively in a uniform magnetic field \(B\). The relation between \(r_e,r_p,r_\alpha\)is:
1. \( r_e>r_p=r_\alpha \)
2. \( r_e<r_p=r_\alpha \)
3. \( r_e<r_p<r_\alpha \)
4. \( r_e<r_\alpha<r_p \)
Subtopic: Lorentz Force |
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A proton, an electron, and a helium nucleus have the same energy. They are in circular orbits in a plane due to a magnetic field perpendicular to the plane. Let \(r_p\), \(r_e\) and \(r_{\mathrm{He}}\) be their respective radii, then:
1. \( r_{\mathrm{e}}<r_p<r_{H e} \)
2. \( r_e>r_p=r_{H e} \)
3. \( r_e<r_p=r_{H e} \)
4. \( r_e>r_p>r_{H e}\)
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A charged particle moves along a circular path in a uniform magnetic field in a cyclotron. The kinetic energy of the charged particle increases to \(4\) times its initial value. What will be the ratio of the new radius to the original radius of the circular path of the charged particle?
1. \(1:1\)
2. \(1:2\)
3. \(2:1\)
4. \(1:4\)
1. \(1:1\)
2. \(1:2\)
3. \(2:1\)
4. \(1:4\)
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A cyclotron is used to accelerate protons. If the operating magnetic field is 1.0 T and the radius of the cyclotron 'dees' is 60 cm, the kinetic energy of the accelerated protons in MeV will be :
[use mp = 1.6 × 10–27 kg, e = 1.6 × 10–19 C]
1. 12
2. 18
3. 16
4. 32
[use mp = 1.6 × 10–27 kg, e = 1.6 × 10–19 C]
1. 12
2. 18
3. 16
4. 32
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