A ball is traveling with uniform translatory motion. This means that:

A meter scale is moving with uniform velocity. This implies:

A cricket ball of mass 150 g has an initial velocity $\mathrm{u}=(3\hat{\mathrm{i}}+4\hat{\mathrm{j}}){\mathrm{ms}}^{-1}$ and a  final velocity$\mathrm{v}=-(3\hat{\mathrm{i}}+4\hat{\mathrm{j}}){\mathrm{ms}}^{-1}$, after being hit. The change in momentum (final momentum-initial momentum) is (in kgm/s)

\(1.~zero\)
\(2.~-\left ( 0.45\hat{i}+0.6\hat{j} \right ) \)
\(3.~-\left ( 0.9\hat{i}+1.2\hat{j} \right ) \)
\(4.~-5\left ( \hat{i} +\hat{j}\right ) \)

In the previous problem (3), the magnitude of the momentum transferred during the hit is:

1. zero
2. 0.75 kg-ms^-1
3. 1.5 kg-ms^-1
4. 14 kg-ms^-1

Conservation of momentum in a collision between particles can be understood from:

A hockey player is moving northward and suddenly turns westward at the same speed to avoid an opponent. The force that acts on the player is

1. frictional force along westward
2. muscle force along southward
3. frictional force along south-West
4. muscle force a south-West

A body of mass 2kg travels according to the law $\mathrm{x}\left(\mathrm{t}\right)=\mathrm{pt}+{\mathrm{qt}}^2+{\mathrm{rt}}^3$ where, $\mathrm{q}=4{\mathrm{ms}}^{-2},\mathrm{p}=3{\mathrm{ms}}^{-1}\text{ and }\mathrm{r}=5{\mathrm{ms}}^{-3}$. The force acting on the body at t=2s is

1. 136 N
2. 134 N
3. 158 N
4. 68 N

A body with a mass of \(5\) kg is acted upon by a force \(\vec{F}=\left ( -3\hat{i} +4\hat{j}\right )\) N. If its initial velocity at \(t=0\) is \(\vec{v}=\left ( 6\hat{i} -12\hat{j}\right )\) m/s, the time at which it will just have a velocity along the Y-axis is:
1. never
2. \(10\) s
3. \(2\) s
4. \(15\) s

A car of mass m starts from rest and acquires a velocity along the east, \(v=v\mathrm{\hat{i}}(v>0)\) in two seconds. Assuming the car moves with uniform acceleration, the force exerted on the car is:

The motion of a particle of mass m is given by x = 0 for t < 0s, x(t) = A sin 4$\mathrm{\pi }$t for 0 < t < (1/ 4)s (A > 0), and x = 0 for t > (1/4) s. Then:

(a) The force at t = (1/8)s on the particle is $-16{\pi }^{2}Am$
(b) The particle is acted upon by an impulse of magnitude 4${\mathrm{\pi }}^{}$Am at t =0 s and t =(1/4) s
(c) The particle is not acted upon by any force
(d) The particle is not acted upon by a constant force
(e) There is no impulse acting on the particle

Which of the following statement/s is/are true?

1. (a, c, d, e)

2. (a, c)

3. (b, c, d)

4. (a, b, d)