The correct order of increasing reactivity of C-X bond towards nucleophile in the following compound is

[2010]

1. I<II<IV<III

2. II<III<I<IV

3. IV<III<I<II

4. III<II<I<IV

Aniline is reacted with bromine water and the resulting product is treated with an aqueous solution of sodium nitrite in presence of dilute hydrochloric acid. The compound so formed is converted into a tertafluoroborate which is subsequently heated. The final product is    

1. 1,3,5-tribromobenzene

2. p-bromofluorobenzene

3. p-bromoaniline

4. 2,4,6-tribromofluorobenzene

Alkyl halide (RX) on treatment with KCN followed by reduction leads to the formation of:

1. RNH₂

2. RCH₂NH₂

3. RH + NH₃

4. RCH₃ + N₂

The end product in the following sequence of reactions is -

${\mathrm{C}}_2{\mathrm{H}}_5{\mathrm{NH}}_2\stackrel{{\mathrm{HNO}}_2}{\to }A \stackrel{{\mathrm{PCl}}_5}{\to }B\stackrel{{\mathrm{NH}}_3}{\to }C?$
$$

1. Ethyl cyanide

2. Ethylamine

3. Methylamine

4. Acetamide

The product[A] formed in the reaction; $2{\mathrm{C}}_5{\mathrm{H}}_5-\mathrm{CN}\underset{{\mathrm{Et}}_2\mathrm{O}}{\overset{\mathrm{Na}}{\to }} \left[\mathrm{A}\right] \mathrm{is}:\mathrm{C}$

1. 

2. 

3. 

4. 

CH₃CH₂NH₂ contains a basic NH₂ group, but CH₃CONH₂ does not, because;

1. acetamide is amphoteric in character

2. in CH₃CH₂NH₂ the electron pair on N-atom is delocalized by resonance

3. in CH₃CH₂NH₂ there is no resonance, while in acetamide the lone pair of electron on N-atom is delocalized and therefore less available for protonation

4. none of the above

Dehydration of an amide gives:

1. Cyanide

2. Amine

3. Isocyanide

4. Fatty acid

Tertiary nitro compounds cannot show tautomerism because:

1. they are very stable

2. isomerises to give sec. nitro compounds

3. do not have labile H-atom

4. they are highly eactive

A secondary amine is:

1. a compound with two -NH₂ groups

2. a compound with 2 carbon atoms and a -NH₂ group

3. a compound with a -NH₂ group on the carbon atom in number 2 position

4. a compound in which 2 of the hydrogens of NH₃ have been replaced by alkyl or aryl groups

Compound that will undergo Hoffmann reaction is-

1. RCONHCH₃

2. RCOONH₄

3. RCONH₂

4. RCONHOH