Iodoform test is not given by

1. 2-pentanone                 

2. ethanol

3. ethanal                         

4. 3-pentanone

Two isomeric ketones 3-Pentanones and 2-pentanone can be distinguished by

1. I₂/NaOH only               

2. NaHSO₃ only

3. NaCN/HCl                     

4. both of (a) and (b)   

Products of the following reaction                                   

  CH₃C$\equiv$C-CH₂CH₃ $\underset{\left(\mathrm{ii}\right) \mathrm{hydrolysis}}{\overset{\left(\mathrm{i}\right) {\mathrm{O}}_3}{\to }}$ ... are

1. CH₃CHO + CH₃CH₂CHO

2. CH₃COOH + CH₃COCH₃

3. CH₃COOH + HOOC-CH₂CH₃

4. CH₃COOH + CO₂

Which alkene on ozonolysis gives CH₃CH₂CHO and CH₃COCH₃?                                          

1. CH₃CH₂CH=C${<}_{{\mathrm{CH}}_3}^{{\mathrm{CH}}_3}$

2. CH₃CH₂CH=CHCH₂CH₃

3. CH₃CH₂CH=CHCH₃

4. ${\mathrm{CH}}_3-\underset{|}{\mathrm{C}}={\mathrm{CHCH}}_3$
${\mathrm{CH}}_3$

The major organic product formed from the following reaction

 $\underset{\left(\mathrm{ii}\right) {\mathrm{LiAlH}}_4 \left(\mathrm{iii}\right) {\mathrm{H}}_2\mathrm{O}}{\overset{\left(\mathrm{i}\right) {\mathrm{CH}}_3{\mathrm{NH}}_2}{\to }}$ ... is

1.                   

2.  

3.                 

4.  

Benzoic acid gives benzene on being heated with X and phenol gives benzene on being heated with Y. Therefore, X and Y are respectively                                                              

1. Sodalime and copper

2. Zn dust and NaOH

3. Cu and sodalime

4. Sodalime and zinc dust

Which one of the following on oxidation gives a ketone?                       

1. primary alcohol                     

2. secondary alcohol

3. tertiary alcohol                     

4. All of these

A carbonyl compound reacts with hydrogen cyanide to form cyanohydrin which on hydrolysis forms a racemic mixture of $\mathrm{\alpha }$-hydroxy acid. The carbonyl compound is

1. acetaldehyde 

2. acetone

3. diethyl ketone 

4. formaldehyde                              

Consider the following transformations

CH₃COOH $\stackrel{{\mathrm{CaCO}}_3}{\to }$A$\stackrel{\mathrm{heat}}{\to }$B$\underset{\mathrm{NaOH}}{\overset{{\mathrm{I}}_2}{\to }}$C The molecular formula of C is                       

1. ${\mathrm{CH}}_3-\underset{\mathrm{I}}{\overset{\mathrm{OH}}{\underset{\left|}{\overset{\right|}{\mathrm{C}}}}}-{\mathrm{CH}}_3$

2. ${\mathrm{ICH}}_2-{\mathrm{COCH}}_3$

3. ${\mathrm{CHI}}_3$

4. ${\mathrm{CH}}_3\mathrm{I}$

 A and B in the following reactions are $\underset{\mathrm{KCN}}{\overset{\mathrm{HCN}/}{\to }}$A$\stackrel{\mathrm{B}}{\to }$

1. A=${\mathrm{RR}}^{\text{'}}{\mathrm{CH}}_2\mathrm{CN}$, B=NaOH

2. A=, B=${\mathrm{CH}}_3$

3. A=, B=${\mathrm{CH}}_3$

4. A=, B=${\mathrm{LiAlH}}_4$