A body starts from rest. What is the ratio of the distance travelled by the body during the 4th and 3rd second 

(1) 75

(2) 57

(3) 73

(4) 37 

Subtopic:  Uniformly Accelerated Motion |
 86%
PMT - 1993
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The acceleration ‘a’ in m/s2 of a particle is given by a=3t2+2t+2 where t is the time. If the particle starts out with a velocity, u = 2 m/s at t = 0, then the velocity at the end of 2 seconds will be:

1. 12 m/s

2. 18 m/s

3. 27 m/s

4. 36 m/s

Subtopic:  Acceleration |
 73%
From NCERT
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A particle moves along a straight line such that its displacement at any time t is given by S=t36t2+3t+4 metres. The velocity when the acceleration is zero is:

1. 4 ms-1 2. −12 ms−1
3. 42 ms−1 4. −9 ms−1
Subtopic:  Acceleration |
 81%
From NCERT
PMT - 1994
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If a body starts from rest and travels 120 cm in the 6th second, then what is the acceleration 

(1) 0.20 m/s2

(2) 0.027 m/s2

(3) 0.218 m/s2

(4) 0.03 m/s2

Subtopic:  Uniformly Accelerated Motion |
 81%
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If a car at rest accelerates uniformly to a speed of 144 km/h in 20 s. Then it covers a distance of 

(1) 20 m

(2) 400 m

(3) 1440 m

(4) 2880 m

Subtopic:  Uniformly Accelerated Motion |
 79%
From NCERT
PMT - 1997
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The position \(x\) of a particle varies with time \(t\) as \(x=at^2-bt^3\). The acceleration of the particle will be zero at time \(t\) equal to:
1. \(\frac{a}{b}\)
2. \(\frac{2a}{3b}\)
3. \(\frac{a}{3b}\)
4. zero

Subtopic:  Acceleration |
 84%
From NCERT
PMT - 1997
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If a train travelling at 72 kmph is to be brought to rest in a distance of 200 metres, then its retardation should be

(1) 20 ms–2

(2) 10 ms–2

(3) 2 ms–2

(4) 1 ms–2

Subtopic:  Uniformly Accelerated Motion |
 82%
From NCERT
PMT - 2004
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The displacement of a particle starting from rest (at t = 0) is given by s=6t2t3. The time in seconds at which the particle will attain zero velocity again, is  

(1) 2

(2) 4

(3) 6

(4) 8

Subtopic:  Instantaneous Speed & Instantaneous Velocity |
 81%
From NCERT
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Two cars A and B are at rest at the same point initially. If A starts with uniform velocity of 40 m/sec and B starts in the same direction with a constant acceleration of 4 m/s2, then B will catch A after how much time?

(1) 10 sec

(2) 20 sec

(3) 30 sec

(4) 35 sec

Subtopic:  Uniformly Accelerated Motion |
 58%
From NCERT
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The motion of a particle is described by the equation x=a+bt2 where a = 15 cm and b = 3 cm/s2. Its instantaneous velocity at time 3 sec will be 

(1) 36 cm/sec

(2) 18 cm/sec

(3) 16 cm/sec

(4) 32 cm/sec

Subtopic:  Instantaneous Speed & Instantaneous Velocity |
 90%
From NCERT
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