Ncert Exercises & Solutions

4.6 A reaction is second order with respect to a reactant. How is the rate of reaction affected if the concentration of the reactant is

(i) doubled (ii) reduced to half ?

NEETprep Answer:

Let the concentration of the reactant be [A] = a
Rate of reaction, R = k [A] $^{2}$
= ka $^{2}$
(i)If the concentration of the reactant is doubled, i.e. $[A] = \frac{1}{2} a$ [A] = 2a, then the rate of the reaction
would be

$R = K {(\frac{1}{2} a)}^{2}$
$= \frac{1}{4} k a$
$= \frac{1}{4} R$

Therefore, the rate of the reaction would be reduced to $\frac{1^{t h}}{4} .$

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