Ncert Exercises & Solutions

Chloromethane on treatment with excess of ammonia yields mainly:

1.	N, N-dimethylmethanamine
2.	N-methylmethanamine (CH₃ —NH—CH₃ )
3.	Methanamine (CH₃ NH₂ )
4.	Mixture containing all these in equal proportion.

Hint: Primary amine is the major product

Chloromethane on reaction with an excess of ammonia reagent produces methamine as the major product.\(\mathrm{CH}_{3} \mathrm{Cl}+\mathrm{NH}_{3}(Excess) \rightarrow \mathrm{CH}_{3} \mathrm{NH}_{2}+\mathrm{HCl} \)

Although, if the two reactants will react in an equal amount, then a mixture of products is formed as a primary, secondary, and tertiary amine.

Here, an excess amount of ammonia is used hence, only primary amine is obtained.

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