Ncert Exercises & Solutions

Chloromethane on treatment with excess of ammonia yields mainly:
1. N, N-dimethylmethanamine
2. N-methylmethanamine (CH $_{3}$ —NH—CH $_{3}$ )
3. Methanamine (CH $_{3}$ NH $_{2}$ )
4. Mixture containing all these in equal proportion

Hint: Primary amine is the major product

Chloromethane on reaction with an excess of ammonia reagent produces methamine as the major product.$\mathrm{CH}_{3} \mathrm{Cl}+\mathrm{NH}_{3}(Excess) \rightarrow \mathrm{CH}_{3} \mathrm{NH}_{2}+\mathrm{HCl} $

Although, if the two reactants will react in an equal amount, then a mixture of products is formed as a primary, secondary, and tertiary amine.

Here, an excess amount of ammonia is used hence, only primary amine is obtained.

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