Ncert Exercises & Solutions

An actinoid that does not have one electron in its 6d orbital is -

1.	U (Atomic number. 92)	2.	Np (Atomic number. 93)
3.	Pu (Atomic number. 94)	4.	Cm (Atomic number. 96)

HINT: All elements belong to actinoids.Pu does not have electron in d- orbitals.

Explanation:

The electronic configuration of U, Np, Pu, and Cm are as follows:

$U = 92,$ $[Rn] 5 f^{3}$ $6 d^{1} 7 s^{2}$
$Np = 93,$ $[Rn]$ $5 f^{4} 6 d^{1}$ $7 s^{2}$
$Pu = 94, [Rn]$ $5 f^{6}$ $7 s^{2}$
$Cm = 96,$ $[Rn]$ $5 f^{7}$ $6 d^{1} 7 s^{2}$

Thus, Pu does not have electron in 6d orbital.

Hence, option third is the correct answer.

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