Ncert Exercises & Solutions

Highest oxidation state of manganese in fluoride is +4(Mn $F_{4}$ ) but highest oxidation state in oxides is +7( $M n_{2} O_{7}$ ) because

1.	Fluorine is more electronegative than oxygen
2.	Fluorine does not possess d orbitals
3.	Fluorine stabilises lower oxidation state
4.	In covalent compounds, fluorine can form single bond only while oxygen forms double bond

Highest oxidation state of manganesein fluoride is +4(Mn

F_{4}

) but highest oxidation state in oxides is +7(

M n_{2} O_{7}

). The reasonis that in covalent compounds fluorine can form single bond while oxygen forms double bond.