Ncert Exercises & Solutions

3.8 The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm–1. Calculate its molar conductivity.

Hint: Use the formula, that is, $\lambda_{m}=\frac{k\times 1000}{C} $

Step 1:

The formula is as follows:

$\lambda_{m}=\frac{k\times 1000}{C} $

Given values are,
k $= 0.0248 S {cm}^{- 1} c$

C= 0.20 M

Step 2:

$∴$ Molar conductivity, $Λ_{m} = \frac{k \times 1000}{c}$

$= \frac{0.0248 \times 1000}{0.2}$

$= 124 {Scm}^{2} {mol}^{- 1}$