Ncert Exercises & Solutions

Match the terms given in Column I with expressions given in Column II.

Column I	Column II
A. Mass percentage	1. $\text{Number of moles of the solute component} \over \text{Volume of solution in litres}$
B. Volume percentage	2. $\text{Number of moles of the solute component} \over \text{Mass of solvent in kilograms}$
C. Molarity	3. ${\text{Volume of the solute component in solution} \over \text{Total volume of solution}} \times 100$
D. Molality	4. ${\text{Mass of the solute component in solution} \over \text{Total Mass of solution}} \times 100$

Codes

Hint: Molarity is defined as the number of moles of solute per litre of solution (moles/Liter)

Column I

(Concentration terms)

Column II

(Mathematical formula)

A. Mass percentage

B. Volume percentage

C. Molality

D. Molarity

1. $\frac{Mass of the solute component in solution}{Total mass of the solution} \times 100$

2. $\frac{Volume of the solute component in solution}{Total volume of solution} \times 100$

3. $Number$ $of$ $moles$ $of$ $the$ $solute$ $components$ $Mass$ $of$ $solvent$ $in$ $kilograms$

4. $Number$ $of$ $moles$ $of$ $the$ $solute$ $component$ $Volume$ $of$ $solution$ $in$ $litres$