Ncert Exercises & Solutions

The correct bond angle for \(\mathrm{sp}^2\) hybridization is:

1.	\(90^\circ\)	2.	\(120^\circ\)
3.	\(180^\circ\)	4.	\(109^\circ\)

HINT: Trigonal planar geometry.

Explanation:

For sp² hybridization, the geometry is generally trigonal planar.

Thus, the bond angle is

120 °