The variation of quantity A with quantity B is plotted in the given figure which describes the motion of a particle in a straight line.
           
Consider the following statements:

a. Quantity B may represent time.
b. Quantity A is velocity if motion is uniform.
c. Quantity A is displacement if motion is uniform.
d. Quantity A is velocity if motion is uniformly accelerated.

Select the correct option:

1. (a, b, c) 2. (b, c, d)
3. (a, c, d) 4. (a, c)

(3) Hint: Recall the concept of uniform motion and uniformly accelerated motion.

Step 1: Find the nature of displacement-time graph in uniform motion.

When we are calculating the velocity of a displacement-time graph we have to take slope similarly we have to take the slope of the velocity-time graph to calculate acceleration.

Step 2: Find the nature of velocity-time graph for uniformly accelerated motion.

When the slope is constant motion will be uniform. When we are representing motion by a graph it may be displacement-time, velocity-time or acceleration-time hence, B may represent time. For uniform motion, the velocity-time graph should be a straight line parallel to the time axis. For uniform motion velocity is constant hence slope will be positive. Hence quantity A is displacement.

For uniformly accelerated motion slope will be positive and A will represent velocity.