Ncert Exercises & Solutions

The electric field intensity produced by the radiations coming from 100 W bulb at a 3 m distance is E. The electric field intensity produced by the radiations coming from 50 W bulb at the same distance is:

1. \(\frac{E}{2}\)

2. \(2E\)

3. \(\frac{E}{\sqrt2}\)

4. \(\sqrt2E\)

(a)

Hint: The intensity of the radiation depends on the power of the bulb.

Step 1: We know that,

E_{0} \propto P_{av}

∴ \frac{E'}{E} = \frac{P_{av}'}{P_{av}}

E' = \frac{50}{100} E = \frac{E}{2}

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