If the RMS current in a \(50~\text{Hz}\) AC circuit is \(5~\text{A}\), the value of the current \(\frac{1}{300}~\text{s}\) after its value becomes zero is:
1. \(5\sqrt2~A\)
2. \(5\sqrt{\frac32}~A\)
3. \(\sqrt{\frac56}~A\)
4. \(\frac{5}{\sqrt2}~A\)

(b) Hint: The current varies periodically in the circuit.
Step 1: Given, ν=50 Hz, Irms=5A
                 t=1300s
We have to find I(t).
Step 2: I0=Peak value=2Irms =2×5
    =52A
Step 3: I=I0sinωt =52sin2πνt=52 sin2×50×1300
  =52sinπ3=52×32=53/2 A