Maxm emf induced = 0.603 V

Avg emf induced = 0 V

Max current in the coil = 0.0603 A

Power loss (average) = 0.018 W

(Power which is coming from external rotor)

Circular coil radius, r = 8 cm = 0.08 m

Area of the coil,$A=\pi r^2=\pi \times (0.08{)}^2{m}^2$${\mathrm{}}^{}$

Number of turns on the coil, N = 20

Angular speed,

Magnetic field strength,

The resistance of the loop, R = 10 $\mathrm{\Omega }$ Maximum induced emf is given as: $\mathrm{e} = \mathrm{N\omega AB}$

$\mathrm{}$$\begin{array}{l}=20\times 50\times \pi \times (0.08{)}^2\times 3\times {10}^{-2}\\ =0.603V\end{array}$

The maximum emf induced in the coil is 0.603 V.

Over a full cycle, the average emf induced in the coil is zero.

The maximum current is given as:

$\begin{array}{l}I=\frac{e}{R}\\ =\frac{0.603}{10}=0.0603A\end{array}$
Average power because of the Joule heating:

$\begin{array}{l}P=\frac{eI}{2}\\ =\frac{0.603\times 0.0603}{2}=0.018W\end{array}$The current induced in the coil produces a torque opposing the rotation of the coil. The rotor is an external agent It must supply torque to counter this torque in order to keep the coil rotating uniformly. Hence, dissipated power comes from the external rotor.