Ncert Exercises & Solutions

Question 2.24:

What is the area of the plates of a 2 F parallel plate capacitor, given that the separation between the plates is 0.5 cm? [You will realize from your answer why ordinary capacitors are in the range of $μ$ F or less. However, electrolytic capacitors do have a much larger capacitance (0.1 F) because of the very minute separation between the conductors.]

The capacitance of a parallel capacitor, V = 2 F

Distance between the two plates, d = 0.5 cm = 0.5 x 10^-2 m

Capacitance Of a parallel plate capacitor is given by the relation,

\begin{array}{l} C = \frac{ϵ_{0} A}{d} \\ A = \frac{Cd}{ϵ_{0}} \end{array}

Where,

ε_{0}

= Permittivity of free space

∴ A = \frac{2 \times 0 .5 \times 10^{- 2}}{8 .85 \times 10^{- 12}} = 1130 {km}^{2}

Hence, the area of the plates is too large.

To avoid this situation, the capacitance is taken in the range of

μ

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