In a two-dimensional motion, instantaneous speed is a positive constant. Then which of the following is necessarily true?
1. | The acceleration of the particle is zero. |
2. | The acceleration of the particle is increasing. |
3. | The acceleration of the particle is necessarily in the plane of motion. |
4. | The particle must be undergoing a uniform circular motion. |
Step 1: Try to prove each option wrong.
\(Let~velocity,\vec{v}=v_{x}\hat{i}+v_{y}\hat{j}\)
\(Now,~acceleration,\vec{a}=\frac{d\vec{v}}{dt}=a_{x}\hat{i}+a_{y}\hat{j}\)
As velocity is in the (x-y) plane so the acceleration of the particle is necessarily in the plane of motion.
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