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In the following reaction the catalyst used is:
         $\to$${\mathrm{C}}_6{\mathrm{H}}_6$ + 3${\mathrm{H}}_2$
1. ${\mathrm{Cr}}_2{\mathrm{O}}_3$                                      2. $A{l}_2{\mathrm{O}}_3$
3. Zn dust                                    4. ${\mathrm{Cr}}_2{\mathrm{O}}_3$ and $A{l}_2{\mathrm{O}}_3$

${\mathrm{CH}}_3-\mathrm{CHCOOK}$
$|$
${\mathrm{CH}}_3-\mathrm{CHCOOK}$$\stackrel{\mathrm{Electrolysis}}{\to }$ A (Major)
The product "A" is -
1.                  2. 
3.                 4. 

Which of the following bromides is the major product of the reaction shown below, assuming that there are no carbocation rearrangement?
$+\mathrm{HBr} \underset{(1 \mathrm{Equivalent})}{\to } {\mathrm{C}}_{13}{\mathrm{H}}_{17}\mathrm{Br}$

_{1. 
2. 
3.
4.} 

$\underset{{\mathrm{R}}_2{\mathrm{O}}_2/\mathrm{hv}}{\overset{\mathrm{HBr}}{\to }}$(A);   
 
Major product (A) is:
(a) 
(b) 
(c) 
(d) 

$\underset{\mathrm{Liq}. {\mathrm{NH}}_3}{\overset{\mathrm{Na}}{\to }} \left(A\right)\underset{\mathrm{Zn}}{\overset{{\mathrm{O}}_3}{\to }}\left(B\right)\stackrel{{\mathrm{Ph}}_3\mathrm{P}={\mathrm{CH}}_2\left(2\mathrm{mole}\right)}{\to }\left(C\right)$
Product (C) of the above reaction is :
(a) 1,3-Hexadiene
(b) 1,4-Pentadiene
(c) 1,3-Butadiene
(d) 1,3-Heptadiene

The reagents used for the following conversion is/are-

 

1.	(i) NaNH2 , (ii) CH3CHO
2.	(i) NaNH2 , (ii) CH3-CH2-CH2-Br
3.	(i) KOH, (ii) CH3-CH2-CH2-Br
4.	(i) KOH, (ii)

Which alkyne will give 3-ethylhexane on catalytic hydrogenation?
1. 
2. 
3. 
4. All of the above

To carry out above conversion, (A) and (B) respectively, are :
(1) NaNH₂, Cl - CH₂ーCH₂ - CH₂ - Br
(2) NaNH₂, CH₂-CH₂-CH₂-Br
(3) NaNH₂, l-CH₂ーCH₂-CH₂-Br
(4) NaNH₂, I-CH₂-CH₂-CH₂-I

 The strongest acid among the following is -

1.		2.
3.		4.

Product (C) is:-
1. 
2. 
3. 
4. 

 Product (A) in this reaction is:
1. 
2. 
3. 
4. 
 

A non-aromatic compound among the following compounds is-

1.		2.
3.		4.

In the above compound, Cl will liberate easily in the form of-
1. ${\mathrm{Cl}}^{\oplus }$
2. Cl^-
3. Cl
4. Cl²⁺

The product (B) in the above-mentioned reaction is-

1.		2.
3.		4.

$\stackrel{{\mathrm{Cl}}_2}{\to }$ (A), Product (A) of this reaction is:
(a) 
(b) 
(c) 
(d) 

p-Toluidine reacts with benzene diazonium chloride to form compound, which on boiling with aq. H₂SO₄ give .......... products:
(1) 3
(2) 2
(3) 4
(4) 5

 The compounds among the following that can be generated by Friedel craft acylation is/are -

I.
II.
III.
IV.

Partial oxidation of methane with Ni/Al₂O₃ catalyst gives:
1. HCHO
2. HCOOH
3. H₂O and CO₂
4. CO and H₂O

What products are formed when the following compound is treated with Br₂ in the
presence of FeBr₃?

1. 
2. 
3. 
4. 

Identity Z in the sequence of reactions,
                          HBr/H₂O₂ 
CH₃CH₂CH=CH₂    →        Y    +   C₂H₅O^-Na⁺→   Z
 
1. CH₃-(CH₂)₃-O-CH₂CH₃

2. (CH₃)₂CH₂-O-CH₂CH₃

3. CH₃(CH₂)₄-O-CH₃

4. CH₃CH₂-CH(CH₃)-O-CH₂CH₃                  

In the following reaction, What will be the major product?

1. 
2.
3. 
4. 

Nitrobenzene can be prepared from benzene by using a mixture of conc. HNO₃ and conc.
H₂SO₄. In the mixture, nitric acid acts as a/an-
1. Reducing agent
2. Acid
3. Base
4. Catalyst

The number of isomeric sodium salt of acid that will be required to obtain neopentane is-
1. 3                                   
2. 1
3. 4                                                  
4. 6
 

      $\stackrel{\mathrm{H}}{\stackrel{|}{{\mathrm{CH}}_2}}-\stackrel{\mathrm{Cl}}{\stackrel{|}{{\mathrm{CH}}_2}}\underset{\mathrm{alc}.}{\overset{\mathrm{NaOH}}{\to }}{\mathrm{CH}}_2={\mathrm{CH}}_2$
The most probable mechanism for this reaction is-
1. E₁                                         
2. E₂
3. $E{1}_{CB}$                                     
4. $\alpha$ elimination

The type of reaction and intermediate of decarboxylation reaction are.-
(1)                                                 
(2) 
(3)                                                  
(4) 

The compound that has the maximum melting point among the following is-
1. ${\mathrm{C}}_4{\mathrm{H}}_{10}$ $$ $$                                 
2. ${\mathrm{C}}_5{\mathrm{H}}_{12}$
3. ${\mathrm{C}}_6{\mathrm{H}}_{14}$ $$                                  
4. ${\mathrm{C}}_7{\mathrm{H}}_{16}$

$\stackrel{1\mathrm{eq}.\mathrm{NBS}}{\to }$ X$\stackrel{{\mathrm{PhO}}^{-}}{\to }$Y (major product)
The product Y is -