The final product C in the below mentioned reaction is:
\(\xrightarrow[]{Ac_2O}\ A\ \xrightarrow[CH_3COOH]{Br_2}\ B\ \xrightarrow[H^+]{H_2O}\ C\)
1. | 2. | ||
3. | 4. |
1. | |
2. | |
3. | |
4. | All of these |
An aromatic amine (A) was treated with alcoholic potash and another compound (Y) when a foul smelling gas was formed with formula C6H5NC. (Y) was formed by reacting a compound (Z) with Cl2 in the presence of slaked lime. Compound (Z) is:
1.
2.
3.
4.
Aniline cannot be prepared by:
1. | Hydrolysis of phenyl isocyanide with an acidic solution |
2. | Degradation of benzamide with bromine in alkaline solution |
3. | Reduction of nitrobenzene with H2/Pd in ethanol |
4. | Treatment of Potassium salt of phthalimide with chlorobenzene followed by hydrolysis in an aqueous NaOH solution |
What results from the electrolytic reduction of nitrobenzene in a highly acidic medium?
1. p-Aminophenol
2. Azoxybenzene
3. Azobenzene
4. Aniline
Nitrobenzene on reaction with conc. HNO3 /H2SO4 at 80 – 100 ºC forms:
1. 1,3– Dinitrobenzene
2. 1,4–Dinitrobenzene
3. 1,2,4–Trinitrobenzene
4. 1,2–Dinitrobenzene
What is the correct order of the methyl-substituted amines' basic strength in an aqueous solution?
1. CH3NH2 > (CH3)2NH > (CH3)3N
2. (CH3)2NH > CH3NH2 > (CH3)3N
3. (CH3)3N > CH3NH2 > (CH3)2NH
4. (CH3)3N > CH3NH2 > (CH3)2NH
The product ‘A’ is
X moles of gas
Hence, the value of ‘X’ is
1. 4
2. 3
3. 2
4. 1
Aniline o-toluidine m-toluidine p-toluidine
(I) (II) (III) (IV)
Correct order of basic strength of the above
compounds is
1. II > IV > III > I
2. IV > III > I > II
3. III > II > IV > I
4. IV > I > III > II
Consider the following reaction,
Choose the correct alternatives about the product(P)
1. Product P contains a cyclic ring with one -bond
2. Product P has an open chain with only one -
bond
3. N-atom in the product is sp2 -hybridised.
4. Product P could be
The final product in the following sequence of reaction
is: