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Consider the following reaction
${\mathrm{CH}}_3-\underset{\underset{{\mathrm{CH}}_3}{|}}{\overset{\stackrel{{\mathrm{CH}}_3}{|}}{\mathrm{C}}}-{\mathrm{CH}}_2-\mathrm{Br}+\mathrm{NaOH}\to \left[\mathrm{X}\right]$
[X] as major product will be:
(1) ${\mathrm{CH}}_3-\underset{\underset{{\mathrm{CH}}_3}{|}}{\overset{\stackrel{{\mathrm{CH}}_3}{|}}{\mathrm{C}}}-{\mathrm{CH}}_2\mathrm{OH}$
(2) ${\mathrm{CH}}_3-\underset{\underset{{\mathrm{CH}}_3}{|}}{\overset{\stackrel{\mathrm{OH}}{|}}{\mathrm{C}}}-{\mathrm{CH}}_3$
(3) ${\mathrm{CH}}_3-\underset{\underset{{\mathrm{CH}}_3}{|}}{\overset{\stackrel{\mathrm{OH}}{|}}{\mathrm{C}}}-{\mathrm{CH}}_2-{\mathrm{CH}}_3$
(4) ${\mathrm{CH}}_3-\underset{\underset{{\mathrm{CH}}_3}{|}}{\overset{\stackrel{\mathrm{OH}}{|}}{\mathrm{C}}}-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\mathrm{OH}$

Which among the following is correctly matched?
(1) C₆H₅-CH₃, o,p-directing group
(2) C₆H₅-NO₂, o,p-direction group
(3) C₆H₅-OH, m-directing group
(4) C₆H₅-Cl, m-directing group

Which among the following is correctly matched?
1. -CH₃, deactivating group
2. -Cl, deactivating group
3. -Br, activating group
4. -NO₂, activating group

Arrange the leaving power of nucleophilic groups in decreasing order:
(i) $\stackrel{⊝}{\mathrm{O}}-\underset{\underset{O}{\left|\right|}}{\overset{\stackrel{O}{\left|\right|}}{S}}-C_6{H}_4-C{H}_3$
(ii) $\stackrel{⊝}{\mathrm{O}}-\underset{\underset{O}{\left|\right|}}{\overset{\stackrel{O}{\left|\right|}}{S}}-C_6{H}_5$
(iii) $\stackrel{⊝}{{\mathrm{N}}_3}$
(iv) $\stackrel{⊝}{\mathrm{Br}}$
Select the correct answer from the codes given below
Codes:
(1) (ii), (i), (iii), (iv)
(2) (ii), (i), (iv), (iii)
(3) (i), (ii), (iv), (iii)
(4) (i), (ii), (iii), (iv)

Which one of the following pairs is correctly matched?
(1) Saytzeff rule, least substituted alkene
(2) Hofmann rule, most substituted alkene
(3) E1cb reaction, Hofmann elimination
(4) E1 reaction, Hofmann elimination

Arrange the reactivity of alcohols in decreasing order for E1 elimination reaction:
(i) ${\mathrm{CH}}_3-\stackrel{\stackrel{\mathrm{OH}}{|}}{\mathrm{C}}\mathrm{H}-{\mathrm{CH}}_3$
(ii) ${\mathrm{CH}}_3-\stackrel{\stackrel{\mathrm{OH}}{|}}{\underset{\underset{{\mathrm{CH}}_3}{|}}{\mathrm{C}}}-{\mathrm{CH}}_3$
(iii) ${\mathrm{C}}_6{\mathrm{H}}_5-\stackrel{\stackrel{\mathrm{OH}}{|}}{\underset{\underset{{\mathrm{CH}}_3}{|}}{\mathrm{C}}}-{\mathrm{CH}}_3$
(iv) ${\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2\mathrm{OH}$
Select the correct anser from the codes given below:
Codes:
(1) (iii), (ii), (iv), (i)
(2) (ii), (iii), (iv), (i)
(3) (ii), (iii), (i), (iv)
(4) (iii), (ii), (i), (iv)

Arrange the reactivity of given alcohols in decreasing order for elimination reaction:
(i) $\underset{\underset{{\mathrm{NO}}_2}{|}}{\mathrm{C}}{\mathrm{H}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\mathrm{OH}$
(ii) ${\mathrm{CH}}_3-{\mathrm{CH}}_2-\underset{\underset{{\mathrm{NO}}_2}{|}}{\mathrm{C}}\mathrm{H}-{\mathrm{CH}}_2\mathrm{OH}$
(iii) ${\mathrm{CH}}_3-{\mathrm{CH}}_2-\underset{\underset{\mathrm{OH}}{|}}{\mathrm{C}}\mathrm{H}-{\mathrm{CH}}_2-\mathrm{CN}$
(iv) ${\mathrm{CH}}_3-\underset{\underset{\mathrm{OH}}{|}}{\mathrm{C}}\mathrm{H}-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\mathrm{CN}$
Select the correct answer from the codes given below:
Codes:
1. (iii), (ii), (iv), (i)
2. (ii), (iii), (iv), (i)
3. (i), (iii), (ii), (iv)
4. (i), (iv), (iii), (ii)

Arrange reactivity of given alcohols in decreasing order for elimination reaction:
(i) $\underset{\underset{{\mathrm{NO}}_2}{|}}{\mathrm{C}}{\mathrm{H}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\mathrm{OH}$
(ii) ${\mathrm{CH}}_3-{\mathrm{CH}}_2-\underset{\underset{{\mathrm{NO}}_2}{|}}{\mathrm{C}}\mathrm{H}-{\mathrm{CH}}_2\mathrm{OH}$
(iii) ${\mathrm{CH}}_3-\underset{\underset{{\mathrm{NO}}_2}{|}}{\mathrm{C}}\mathrm{H}-{\mathrm{CH}}_2-{\mathrm{CH}}_2\mathrm{OH}$
(iv) ${\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_2\mathrm{OH}$
Select the correct answer from the codes given below:
Codes:
(1) (i), (ii), (iv), (iii)
(2) (i), (ii), (iii), (iv)
(3) (ii), (iii), (i), (iv)
(4) (ii), (iii), (iv), (i)

In the given reaction,
$\stackrel{\stackrel{\mathrm{Br}}{|}}{\mathrm{C}}{\mathrm{H}}_2-\mathrm{CH}={\mathrm{CH}}_2 \stackrel{{\mathrm{NaNH}}_2/∆}{\to }\left[\mathrm{X}\right]$
[X] will be:
(1) ${\mathrm{CH}}_3-\mathrm{C}\equiv \mathrm{CH}$
(2) ${\mathrm{H}}_2\mathrm{C}=\mathrm{C}\equiv {\mathrm{CH}}_2$
(3) ${\mathrm{CH}}_3-\mathrm{C}\equiv \stackrel{⊝}{\mathrm{C}} \stackrel{\oplus }{\mathrm{Na}}$
(4) ${\mathrm{H}}_2\mathrm{C}=\mathrm{C}\equiv \stackrel{⊝}{\mathrm{C}}\mathrm{H} \stackrel{\oplus }{\mathrm{Na}}$

In the given reaction:
${\mathrm{CH}}_3-{\mathrm{CH}}_2-\stackrel{\stackrel{\mathrm{Br}}{|}}{\mathrm{C}}\mathrm{H}-\mathrm{CH}={\mathrm{CH}}_2\stackrel{\mathrm{alc}. \mathrm{KOH}/∆}{\to }\left[\mathrm{X}\right]$
[X] will be:
(1) ${\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{CH}-\mathrm{C}={\mathrm{CH}}_2$
(2) ${\mathrm{H}}_2\mathrm{C}=\mathrm{CH}-{\mathrm{CH}}_2-\mathrm{CH}={\mathrm{CH}}_2$
(3) ${\mathrm{CH}}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}={\mathrm{CH}}_2$
(4) ${\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\mathrm{C}=\mathrm{CH}$