What volume of H2 is liberated under similar conditions which released 2.24 dm3 O2 by electrolysis of water?
(1) 2.24 dm3
(2) 1.12 dm3
(3) 4.48 dm3
(4) 0.56 dm3
How many moles of sodium carbonate is formed by decomposing 0.2 mole sodium
bicarbonate completely?
1. 0.1
2. 0.2
3. 0.4
4. 0.05
200 ml of 1 M HCl solution is diluted so that the final molarity is 0.5 M. The volume of water added for dilution is
(1) 100
(2) 400
(3) 200
(4) 50
5 g of NaOH is added in 200 ml of water. The molarity of resultant solution will be
1. 1 M
2. 0.725 M
3. 0.825 M
4. 0.625 M
Find the volume of CO required to reduce 0.25 mole ferric oxide as per the given equation
Fe2O3+3CO2Fe+3CO2
(1) 16.8 dm3
(2) 67.2 dm3
(3) 22.4 dm3
(4) 44.8 dm3
What is the mass % of a solute in the solution obtained by dissolving 8 g of solute in 60 g of water?
1. 4.57%
2. 9.1%
3. 11.76%
4. 12.78%
In Haber's process N2+3H2 2NH3, starting with 5L of N2 at STP and 5L of H2, the limiting reagent will be
1. N2
2. H2
3. Both N2 and H2
4. Neither N2 nor H2
50 g of a sample of Ca ¡s dissolved in 50 ml of O.5N HCl solution. The excess of HCl was neutrilized by 0.3N NaOH. The volume of NaOH used was 20cc. Calculate the percentage purity of Ca
(=40, = 16, = 1)
1. 14%
2. 1.4%
3. 0.14%
4. None of these
3 mole H2 is treated with x mole O2 to form 85 gm of . What is the value of x?
1. 2.5
2. 3
3. 3.5
4. 4
Which of the following has maximum number of moles?
1.
2.
3. 18 g gulcose
4.
25 ml of a solution containing HCl and required 10 ml of a 1 N NaOH solution for neutralization. 20 ml of the same acid mixture on being treated with an excess of gives 0.1435 g of AgCl. The normality of HCl and normality of the are respectively
1. 0.40 N and 0.05 N
2. 0.05 N and 0.35 N
3. 0.05 N and 0.25 N
4. 0.40 N and 0.5 N
x g of NaHCO3 is treated with 600 ml of HCl and the excess of HCl is further neutralized by 100 ml of NaOH.
Then the value of x would be
(1) 60
(2) 40
(3) 31
(4) 21
How much minimum volume of oxygen will be required for complete combustion of 60 ml of ethylene enter (CH2=CH2)
(1) 150 ml
(2) 170 ml
(3) 190 ml
(4) 180 ml
x g of is treated with 400 ml , when all the is converted into . The value of x would
1. 0.2
2. 0.8
3. 1.2
4. 2
\(NaOH\,+\,H_{2}CO_{3}\,\to \,NaHCO_{3}\,+\,H_{2}O\)
x g NaOH when treated with excess of H2CO3 forms 100 milliequivalent of NaHCO3. The value of x would be:
1. 4
2. 8
3. 10
4. 12