Please be patient as the PDF generation may take upto a minute.

The D in the above-mentioned reaction is -

1.		2.
3.		4.

The monochlorinated products (excluding stereo-isomers) obtained from the reaction is:

1. 4 
2. 5 
3. 6 
4. 7
 

The reaction of toluene with ${\mathrm{Cl}}_2$ in the presence of ${\mathrm{FeCl}}_3$ gives 'X' and reaction in presence of light gives 'Y'. Thus, 'X' and  'Y' are
1. X = benzal chloride, Y= o-chlorotoluene
2. X = m-chlorotoluene, Y= p-chlorotoluene
3. X = o and p-chlorotoluene, Y = trichloromethyl benzene
4. X = benzal chloride, Y = m-chlorotoluene

Xylene, on oxidation with acidic ${\mathrm{KMnO}}_4$, gives:

Consider the following reaction sequence
$\stackrel{{\mathrm{HNO}}_3+{\mathrm{H}}_2{\mathrm{SO}}_4}{\to } \stackrel{Sn+HCl}{\to }\underset{\left(6H\right)}{\overset{NaN{O}_2+HCl}{\to }}\stackrel{C{u}_2{\left(CN\right)}_2+HCN}{\to }\stackrel{H_{2}O}{\to }Product$
 
Product is

(1)
(2)
(3)
(4)

The products R and S are respectively

(1)
(2)
(3)
(4)

A compound that gives an optically inactive compound on treatment with H₂(2 moles)/ Pt is-
1. 3-Methyl-1-pentyne
2. 4-Methyl-1-hexyne
3. 3-Methyl-1-heptyne
4. None of the above

The final product in the above sequence of reactions is-

1.
2.
3.
4.

The compound among the following that undergoes bromination of its aromatic ring
(electrophilic aromatic substitution) at the fastest rate is-

1.		2.
3.		4.

The major product obtained in the given reaction is-
  
 

1.		2.
3.		4.

A compound among the following that does not undergo Friedel-Craft's reaction easily is-
1. Cumene               
2.  Xylene
3. Nitrobenzene         
4. Toluene

The compound ${\mathrm{C}}_7{\mathrm{H}}_8$ undergoes the following reactions
${\mathrm{C}}_7{\mathrm{H}}_8\stackrel{3{\mathrm{Cl}}_2/\mathrm{hv}}{\to }\mathrm{A}\stackrel{{\mathrm{Br}}_2/\mathrm{Fe}}{\to }\mathrm{B}\stackrel{\mathrm{Zn}/\mathrm{HCl}}{\to }$ C
The product 'C' is-
1. m–Bromotoluene
2. o–Bromotoluene
3. 3–Bromo–2,4,6–trichlorotoluene
4. p–Bromotoluene